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Artemon [7]
3 years ago
13

How is it possible for dark matter to bend reality in space?

Physics
1 answer:
LuckyWell [14K]3 years ago
7 0

Answer:

A: Dark matter is called “dark” because it doesn’t give off or interact with light — including through scattering. It is simply the nature of dark matter and why it is so difficult to study. But some models of dark matter state that on rare occasions, dark matter particles could be capable of interacting with normal matter, including by scattering light.

Astronomers know that dark matter is largely situated in spherical halos that enclose galaxies (more on that in a moment). If the dark matter in that halo scatters the galaxy’s starlight, even rarely, it could create a dim glow, like the halo of a light seen in thick fog. Researchers have searched for that glow but so far have not seen it. One possibility is that the glow is difficult to see at optical wavelengths, which is where past studies have focused. Scientists think such a glow, if it exists, might be easier to detect at longer infrared wavelengths, but no studies with the sensitivity needed to see this faint scattered light have been performed yet.  

However, dark matter does have mass and its gravity can influence matter and light. So, dark matter does contribute to a phenomenon called gravitational lensing, in which a galaxy’s mass — including both its normal and dark matter — causes the space-time around it to curve. As light from an object in the background, such as a more distant galaxy, encounters this curved space-time, it appears to bend, which distorts and can even multiply the image of the background object. Astronomers do observe this effect, and by comparing the amount of gravity necessary to do the bending with the amount of visible matter, they have used it to confirm that galaxies are enshrouded in massive halos of dark matter.

Explanation:

TODO IS HERE BUT THAT QUESTION IS SH_T

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3 years ago
The average intensity of light emerging from a polarizing sheet is 0.708 W/m2, and that of the horizontally polarized light inci
Pachacha [2.7K]

Answer:

Angle θ = 30.82°

Explanation:

From Malus’s law, since the intensity of a wave is proportional to its amplitude squared, the intensity I of the transmitted wave is related to the incident wave by; I = I_o cos²θ

where;

I_o is the intensity of the polarized wave before passing through the filter.

In this question,

I is 0.708 W/m²

While I_o is 0.960 W/m²

Thus, plugging in these values into the equation, we have;

0.708 W/m² = 0.960 W/m² •cos²θ

Thus, cos²θ = 0.708 W/m²/0.960 W/m²

cos²θ = 0.7375

Cos θ = √0.7375

Cos θ = 0.8588

θ = Cos^(-1)0.8588

θ = 30.82°

4 0
3 years ago
Discuss five occasions when people dance ​
Xelga [282]

Answer:

Party, Birthday, Weddings, Nightclub, Just for fun

7 0
3 years ago
The speed of sound in aluminum is 5200 m/s. Can you hear a sound with a
romanna [79]

Answer:

v = wavelength * frequency

frequency = 5200 m/s / .2 m = 26000 / sec

20,000 / sec is optimistic for the upper frequency of human hearing

So 26,000 is above the hearing range for human ears

5 0
2 years ago
A potential difference of 107 mV exists between the inner and outer surfaces of a cell membrane. The inner surface is negative r
sergij07 [2.7K]

Answer:

The workdone is  W = 1.712 *10^{-20 } \  J  

Explanation:

From the question we are told that

    The potential difference is  V  =  107 mV =  107 *10^{-3} \  V

Generally the charge on  Na^{+} is  Q_{Na^{+}} = 1.60 *10^{-19 } \  C

 Generally the workdone is mathematically represented as

         W =  Q_{Na^{+}}V

=>     W = 1.60 *10^{-19 } *  107 *10^{-3}    

=>     W = 1.712 *10^{-20 } \  J    

8 0
3 years ago
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