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3 years ago

7

A man is chased by a bull in a field at a speed of 10m/s for 60 seconds.How far does he get before he is gored by the annoyed bo

vine?

1 answer:

Vsevolod [243]3 years ago

5 0

60 times 10 =600 well if u multiply 60 times 10 it will=600

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A steel ball rolls with constant velocity on a tabletop 1.95 m high. It rolls off and hits the ground 0.5 m away from the edge o

Alex777 [14]

Answer:

0.79 m/s

Explanation:

First of all, we analyze the vertical motion of the ball. It is a free fall motion, so its vertical displacement is given by

$s=ut+\frac{1}{2}at^2$

where

s = 1.95 m is the displacement

u = 0 is the initial vertical velocity

t is the time

$a=g=9.8 m/s^2$ is the acceleration of gravity

Solving for t, we find the time it takes for the ball to reach the ground:

$t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(1.95)}{9.8}}=0.63 s$

Now we can analyze the horizontal motion: this is a uniform motion with constant speed, so the horizontal distance covered by the ball is

$d=v_x t$

where

d = 0.5 m is the horizontal distance covered

t = 0.63 s is the time

Solving for vx, we find the horizontal velocity of the ball:

$v_x = \frac{d}{t}=\frac{0.5}{0.63}=0.79 m/s$

And this velocity is constant during the motion, so the ball was moving at 0.79 m/s when it rolls off the table.

5 0

3 years ago

When a virtual image is created in a plane mirrora. the image is upright.b. the image is located behind the mirror.c. reflected

zubka84 [21]

<h2>Answer: all of the above</h2>

A plane mirror is a highly polished flat surface with a very high capacity to reflect incident light.

According to the figure attached:

1. The incident rays coming from the real object reach the mirror and

2.are reflected following the law of Reflection.

3.The prolongation of those reflected rays converge at a point that <u>does not coincide</u> with the actual position of the object. At that point the virtual image of the object is formed.

4.Then, the reflected divergent rays are captured by our eye converging on the retina.

Now, the image is said to be <u>virtual</u> because it is a copy of the object that looks as if the object is behind the mirror and not in front of it or on the surface, but it is not really there. However, it can be seen when we focus it with our eyes.

In addition, the image formed is:

symmetrical, because apparently it is at the same distance from the mirror

the same size as the object.

upright, because it retains the same orientation as the object.

All these characteristics coincide with the first three options proposed in the question, so the correct option is d.

4 0

3 years ago

A shield of material that reflects neutrons is placed around a radioactive sample.

nikitadnepr [17]

The answer is A. just took the test

3 0

3 years ago

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Define temperature<br> define absolute zero

mars1129 [50]

Answer:

Temperature is a measure of the average energy of molecular motion in a substance. In everyday usage, temperature indicates a measure of how hot or cold an object is. Temperature is an important parameter in chemistry. When a substance changes from solid to liquid, it is because there was in increase in the temperature of the material. Chemical reactions usually proceed faster if the temperature is increased.

Absolute zero is the lowest temperature in Kelvin which all motion stops. Absolute zero is called 0 Kelvin (0 K), and it is equivalent to –273.15°C or –459.67°F.

4 0

3 years ago

Speakers A and B are vibrating in phase. They are directly facing each other, are 8.0 m apart, and are each playing a 75.0-Hz to

NeX [460]

Answer:

4 m, 1.71 m and 6.29 m

Explanation:

Let L = 8 m be the distance between the two speakers. Let x be the distance from speaker A of constructive interference. The distance to speaker B from the point of constructive interference is thus x₁ = L - x.

There is constructive interference when the distance x₁ - x = nλ where n = is an integer and λ = wavelength L - x

x₁ - x = nλ

L - x - x = nλ

L - 2x = nλ

x = (L - nλ)/2 = (L - nv/f)/2. where v = speed of wave = 343 m/s and f = frequency = 75 Hz

The distance from A where constructive interference would occur starts from when

n = 0

x₂ = (L - nv/f)/2 = (8 - 0 × 343/75)/2 = (8 - 0)/2 = 8/2 = 4 m

n = 1

x₃ = (L - nv/f)/2 = (8 - 1 × 343/75)/2 = (8 - 4.57)/2 = 3.43/2 = 1.71 m

when n = 2

x₄ = (L - nv/f)/2 = (8 - 2 × 343/75)/2 = (8 - 9.14)/2 = -1.15/2 = -0.57 m

So the value at n = 2 is not included.

The third point occurs at x₅ = L - x₃ where x₃ = 1.71 m is the distance away from point B where constructive interference also occurs. (since it is symmetrical about the point x₂ = 4 m

x₅ = L - x₃ = 8 - 1.71 = 6.29 m

8 0

3 years ago

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