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icang [17]
3 years ago
15

A type of spectroscopy used to analyze pigments in a painting is:

Chemistry
2 answers:
lorasvet [3.4K]3 years ago
7 0

I would say the answer is D

Paint samples received by forensic laboratories are usually in the form of small chips or smears. Infrared (IR) spectroscopy is one of the most commonly used tools available for the analysis of these types of samples and serves as a staple comparative technique in the assessment of whether or not a questioned sample could have come from a suspected object

The most direct way to probe the vibrational frequencies of a molecule is through infrared spectroscopy. This is because vibrational transitions typically require an amount of energy that corresponds to the infrared region of the spectrum. Raman spectroscopy, which typically uses visible light, can also be used to directly measure vibration frequencies.

4vir4ik [10]3 years ago
7 0

Answer:

d) Infrared absorption

Explanation:

Spectroscopy involves the study of the interaction of electromagnetic radiation with matter.  The electromagnetic spectrum is essentially a composite of photons of different wavelengths and frequencies; from the low wavelength gamma rays to the high wavelength radio waves.

The pigments in a painting are organic compounds which can be easily identified via Infrared spectroscopy. When a beam of infrared light (photons in the 700 nm-1000 nm of the electromagnetic spectrum) is passed through the painting, photons of particular wavelengths or energy which are in resonance with the molecular vibrations of the pigment molecules get absorbed whereas the rest of the IR radiation is reflected and directed onto a detector. A plot intensity of the reflected IR light vs wavelength corresponds to the IR spectrum which is unique to a particular chemical substance. Thus, various pigments in a painting that have IR active features can be identified by this method.

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When 70.4 g of benzamide (C7H7NO) are dissolved in 850. g of a certain mystery liquid X, the freezing point of the solution is 2
Arlecino [84]

Answer:

1.62

Explanation:

From the given information:

number of moles of benzamide  =\dfrac{70.4 \ g}{121.14 \ g/mol}

= 0.58 mole

The molality = \dfrac{mass \ of \ solute (i.e. \ benzamide )}{mass \ of \ solvent  }

= \dfrac{0.58 }{0.85 }

= 0.6837

Using the formula:

\mathbf {dT  = l   \times  k_f  \times m}

where;

dT = freezing point = 27

l = Van't Hoff factor = 1

kf = freezing constant of the solvent

∴

2.7 °C = 1 × kf ×  0.6837 m

kf = 2.7 °C/ 0.6837m

kf = 3.949 °C/m

number of moles of NH4Cl = \dfrac{70.4 \ g}{53.491 \  g /mol}

= 1.316 mol

The molality = \dfrac{1.316 \ mol}{0.85 \ kg}

= 1.5484

Thus;

the above kf value is used in determining the  Van't Hoff factor for  NH4Cl

i.e.

9.9 = l × 3.949 × 1.5484 m

l = \dfrac{9.9}{3.949 \times 1.5484 \ m}

l = 1.62

5 0
3 years ago
What is the democritus findings?
Volgvan

nvm

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4 0
3 years ago
a lab is performed to do the study of pH and heat on the function of the catalase enzyme found in carrot plants. what would be c
ad-work [718]
It would be the ph and heat
3 0
3 years ago
How many Joules must be removed to condense 150.0g of steam at 100.0 degrees Celsius to water at 100.0 degrees celcius
Elina [12.6K]

Answer:

339kJ

Explanation:

Given parameters:

Mass of steam  = 150g  = 0.15kg

Initial temperature of steam  = 100°C

Final temperature of water  = 100°C  

Unknown:

Quantity of heat that must be removed to condense the steam = ?

Solution:

The heat involved here is a latent heat because there is no change temperature. The process is just a phase change.

  H  = mL

m is the mass

L is the latent heat of vaporization  = 2,260 kJ/kg

Insert the parameters and solve;

 H = 0.15kg x 2,260 kJ/kg

 H  = 339kJ

7 0
3 years ago
Which of the following hypotheses cannot be tested using the scientific method
Arturiano [62]
I believe it's answer #3. Logically, at least.

You can test #1 through trial and error.
You can experiment #2 also through trial and error.
You cannot test #3 through trial and error, because that would be catastrophic.
You can test #4 through a survey and individual study and data collection.
7 0
3 years ago
Read 2 more answers
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