<h3>
Answer:</h3>
12.387 moles
<h3>
Explanation:</h3>
We are given;
Temperature of chlorine, T = 120°C
But, K = °C + 273.15
Therefore, T = 393.15 K
Pressure, P = 33.3 Atm
Volume, V = 12 L
We are required to calculate the number of moles of chlorine gas,
To find the number of moles we are going to use the ideal gas equation;
PV = nRT
R is the ideal gas constant, 0.082057 L.atm/mol.K
Therefore, rearranging the formula;
n = PV÷RT
Hence;
n = (33.3 atm × 12 L) ÷ (0.082057 × 393.15 K)
= 12.387 moles
Therefore, the number of moles of chlorine are 12.387 moles
Answer:
it shows the breakdown of the atom
Explanation:
it will show it molecularly
Answer:
Explanation:
The kPa-kilopascal is the unit of pressure. It was named after Blaise Pascal, a mathematician and physicist.
The kPa is 1000Pa. Kilo stands for 1000. Now what is a pascal?
A pascal is the amount of force(Newton) exerted per unit area.
1Pa = 1Nm⁻²
At the standard atmospheric level, the pressure is 101.325 x 10³ Nm⁻² i.e the atmosphere exerts a pressure of 101.325 x 10³N in an area of a body.
This unit is used to calculate pressure. It can be converted to other units.
MNaHCO₃: 23+1+12+(48×3) = 84g
mCH₃COOH: 12+(1×3)+12+(16×2)+1 = 60g
.................
84g NaHCO₃ react with 60g CH₃COOH
83g NaHCO₃ react with...........
84g ----- 60g
83g ----- X
X = 59,29g CH₃COOH
We used 70g CH₃COOH, it' too much.
So, acetic acid is excess reagent, and sodium bicarbonate is limiting reagent.
_______________________________
B) Amount of CH3COOH is in excess.
:•)
To determine the number of moles(n) of a substance, divide its amount given in grams by the molar mass. The element in the problem is gold (Au) which has a molar mass of 196.97 grams per mole. The division is better illustrated below
n = 35.12 g / 196.97 grams per mole
The answer to the operation above is 0.1783 moles. Therefore, there are approximately 0.1783 moles of Au in 35.12 grams.
