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Pie
3 years ago
5

How many grams of co2 are contained in 550 ml of the gas at stp?

Chemistry
1 answer:
dybincka [34]3 years ago
4 0
V = 550 mL = 0.550 L
V = 22.4 L/mol   (STP)
M(CO₂)=44.01 g/mol

n(CO₂)=v/V

m(CO₂)=n(CO₂)M(CO₂)=vM(CO₂)/V

m(CO₂)=0.550*44.01/22.4=1.08 g
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Answer:

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Explanation:

First convert Concentration from ppm inM or mol/l

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⇒ 4.48 ppm = 4.48 mg/l = 4.48 x 10⁻³ g/l

⇒ Molarity = \frac{4.48 X10^{-3} }{158.03X 1(lit)} = 2.83 x 10⁻⁵ molar

Absorbance (A) = - log(T)     ( T = % transmittance)

                          = - log(0.859)

                          = 0.06

According to Lambert Beer's law

     

                 ε = \frac{A}{C X l}

      or,      ε = \frac{0.06}{2.83 X 10^{-5}X1 cm }

      or,      ε = 2120.14 cm⁻¹M⁻¹

Where

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    A = absorbance

    C = Molar concentration of KMnO₄ solution

     l = length  

6 0
3 years ago
If you lived in Alaska, which of the following natural gases could you keep in an outdoor storage tank in winter: a. Methane (CH
wariber [46]

Answer:

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Explanation:

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The reason is the extreme low temperature during the winter. The boiling point of butane is 44 ºF ( -1ºC) and that of propane is a higher -43.6 º F but still within the range of average minimum winter temperature in Alaska (-50 ªF). Therefore we will have condensation in the tanks and not enough gas pressure.

Methane having  a boling point  of  -259 ºF will not condense at the low wintertime temperatures in Alaska.

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Xelga [282]
The answer to this question is 45
4 0
3 years ago
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KatRina [158]

<u> </u> The pH of 0.035 M aqueous aspirin is 2.48

<u>Explanation:</u>

We are given:

Concentration of aspirin = 0.035 M

The chemical equation for the dissociation of aspirin (acetylsalicylic acid) follows:

               HC_9H_7O_4\rightleftharpoons H^++C_9H_7O_4^-

<u>Initial:</u>         0.035

<u>At eqllm:</u>    0.035-x        x         x

The expression of K_a for above equation follows:

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We are given:

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Putting values in above expression, we get:

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Neglecting the value of x = -0.0037 because concentration cannot be negative

So, concentration of H^+ = x = 0.0033 M

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pH=-\log[H^+]

We are given:

H^+ = 0.0033 M

Putting values in above equation, we get:

pH=-\log(0.0033)\\\\pH=2.48

Hence, the pH of 0.035 M aqueous aspirin is 2.48

7 0
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I looked this up but hope it helps
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