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3 years ago

How many grams of co2 are contained in 550 ml of the gas at stp?

1 answer:

4 0

V = 550 mL = 0.550 L
V = 22.4 L/mol (STP)
M(CO₂)=44.01 g/mol

n(CO₂)=v/V

m(CO₂)=n(CO₂)M(CO₂)=vM(CO₂)/V

m(CO₂)=0.550*44.01/22.4=1.08 g

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What does graduated mean when talking about cylinders and beakers

Juliette [100K]

Has markings along the cylinder/beaker that indicate the volume of liquid inside them. .

7 0

3 years ago

a solution of HCI contains 36 percent HCI,by mass and calculate the mole fraction of HCI in the solution?

denis-greek [22]

Explanation:

You have a solution that contains 36 g HCl dissolved in 64 g water

Molar mass HCl = 36.45 g/mol

Mol HCl in 36 g = 36 g / 36.45 g/mol = 0.9876 mol

Molar mass H2O = 18 g/mol

Mol H2O in 64 g = 64 g / 18 g/mol = 3.5556 mol

Total mol = 0.9875 + 3.5556 = 4.5431 mol

Mol fraction HCl = 0.9876 mol / 4.5431 mol = 0.2174

Mol fraction H2O = 3.5556 / 4.5431 = 0.7826

The answer should have 2 significant digits:

Mol fraction HCl = 0.22

Mol fraction H2O = 0.78

Mol fraction has no units.

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4 0

2 years ago

The edge of the card measures 2.5 inches, what is it in cm?

Citrus2011 [14]

Answer:

6.35 centimeters

Explanation:

2.5 inches = 6.35 centimeters

Formula:

multiply the value in inches by the conversion factor '2.54'.

So, 2.5 inches = 2.5 × 2.54 = 6.35 centimeters.

4 0

1 year ago

If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?

ICE Princess25 [194]

Answer: The half life of the sample of silver-112 is 3.303 hours.

Explanation:

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

$k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}$

where,

k = rate constant = ?

t = time taken = 1.52 hrs

$[A_o]$ = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

$k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}$

To calculate the half life period of first order reaction, we use the equation:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life period of first order reaction = ?

k = rate constant = $0.2098hr^{-1}$

Putting values in above equation, we get:

$t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs$

Hence, the half life of the sample of silver-112 is 3.303 hours.

6 0

3 years ago

A pH change can be evidence that

drek231 [11]

Answer:

Explanation:

The acid level has changed

3 0

3 years ago