Answer : The specific heat of fools gold is .
Solution : Given,
Molar specific heat of fools gold =
Formula weight of fools gold = 119.98 g/mole
Formula used :
Molar specific heat substance = Specific heat of substance × Formula weight of substance
Now we have to calculate the specific heat of fools gold.
Now put all the given values in this formula, we get
Therefore, the specific heat of fools gold is .
Answer:
-2.74°C
Explanation:
From the formula;
∆T= Kf m i
Where Kf= freezing constant of water
m= molality of the solution = number of moles of solute/ mass of solvent in kilogram
Since number of moles of solute = 3.68 mol and mass of solvent= 2.5Kg
m= 3.68/2.5 = 1.472
Then the freezing constant Kf= -1.86 as given in the question
Since the solution is not ionic, the Vant Hoft factor (i) = 0
Hence;
∆T= Kf m
∆T= -1.86 × 1.472
∆T= -2.74°C
Answer:
E=1.1
Explanation:
let's consider moles of E is X
3(0.20)+5(0.30)+0.10 =2X
2.2=2X
x=1.1
Answer:
An increase in the carbon dioxide concentration increases the rate at which carbon is incorporated into carbohydrate in the light-independent reaction, and so the rate of photosynthesis generally increases until limited by another factor.
Explanation:
Answer:
im sorry im bored can we talk
Explanation:
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