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Butoxors [25]
3 years ago
13

Select the correct answer from each drop-down menu.

Chemistry
2 answers:
kirza4 [7]3 years ago
7 0

The medium sized puddle of spilled hot water has the highest vapor pressure because vapor pressure depends on temperature of the object.

Answer: B

Explanation

Vapor pressure, the pressure of vapor molecules of liquid exerting on the liquid surface.

It helps to determine the evaporation rate, the more the vapor pressure the more rate of evaporation will occur.

This is because the vapor pressure is the quantification of vapor molecules of the liquid on the surface of the liquid on giving an external force like heat.

The vapor pressure depends on liquid temperature and liquid surface area and pressure.

So in the given case, rainwater puddle has small surface area and room temperature, spilled hot water puddle has higher surface area as well as temperature compared to rain water puddle.

Even though the cold water puddle has large surface area but the temperature of cold water is very less compared to the temperature of hot water, so it makes the medium sized hot water puddle the one with the highest vapor pressure as the vapor pressure depends on temperature of the liquid.

tankabanditka [31]3 years ago
3 0

Answer:

The medium-sized puddle of spilled hot water has the highest vapor pressure

Explanation:

The evaporation of water is a clear example of phase change from liquid to gas. The chemicals potentials for both phases α (liquid) and β (vapor) are functions dependig of the temperature (T) and the pressure (P) and they have the same value.

μα(T,P) = μβ(T,P)

Based in that assumption is that the equation of Clausius Clapeyron:

Ln Pv = - L/(RT) +C

Being Pv, the vapor pressure. L the vapor entalpy and R the gas constant.

So, the vapor pressure is a mere function of the temperature, thus if the temperature rises, the vapor pressure increases.

With that said, the puddle of hot water, has more temperature and thus, a higher vapor pressure.

Hope it helped!

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Answer:

The limiting reactant is the propane gas, C₃H₈ while the percentage yield is 83.77%

Explanation:

Here we have

Propane gas with molecular formula C₃H₈, molar mass  = 44.1 g/mol combining with O₂ as follows

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Therefore, 1 mole of C₃H₈  combines with 5 moles of O₂ to produce 3 moles CO₂ and 4 moles of H₂O

Mass of propane = 0.1240 kg = 124.0 g

Number of moles of propane = mass of propane/(molar mass of propane)

The number of moles of propane = 124/44.1 = 2.812 moles

The molar mass of CO₂ = 44.01 g/mol

Mass of CO₂ = 0.3110 kg = 311.0 g

Therefore, number of moles of CO₂ = mass of CO₂/(molar mass of CO₂)

The number of moles of CO₂ = 311.0 kg/ 44.01 g/mol = 7.067 moles

Therefore, since 1 mole of propane produces 3 moles of CO₂, 2.812 moles of propane will produce 3 × 2.812 moles or 8.44 moles of CO₂

Therefore;

The limiting reactant is the propane gas, C₃H₈, since the oxygen is in excess

Hence

The \ percentage \ yield = \frac{Actual \, yield}{Theoretical \, yield} \times 100 = \frac{7.067}{8.44} \times 100 = 83.77 \%

The percentage yield = 83.77%.

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Explanation:

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The liquid starts boiling or evaporation takes place when the vapor pressure of the liquid becomes equal to the external or atmospheric pressure. Now when the vapor pressure is less than the atmospheric pressure, the liquid boils at a higher temperature while when vapor pressure is more than the atmospheric temperature, the liquid starts boiling a lower temperature.

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