By any method you choose, determine your average speed of walking

PLEASE SOLVE QUICKLY!!!<br> Solve for A, B, and C from graph

hram777 [196]

A = 59.35cm

B = 196.56g

C = 74.65g

<u>Explanation:</u>

We know,

$x = \frac{L}{\frac{W}{F} +1}$

and L = x+y

1.

Total length, L = 100cm

Weight of Beam, W = 71.8g

Center of mass, x = 49.2cm

Added weight, F = 240g

Position weight placed from fulcrum, y = ?

$L-y = \frac{L}{\frac{W}{F}+1 } \\100 - y = \frac{100}{\frac{71.8}{49.2}+1 } \\100 - y = \frac{100}{1.46+1}\\\\100 - y = \frac{100}{2.46} \\100-y = 40.65\\\\y = 59.35cm$

Therefore, position weight placed from fulcrum is 59.35cm

2.

Total length, L = 100cm

Center of mass, x = 47.8 cm

Added weight, F = 180g

Position weight placed from fulcrum, y = 12.4cm

Weight of Beam, W = ?

$47.8 = \frac{100}{\frac{W}{180}+1 }\\\47.8 = \frac{100}{\frac{W+180}{180} } \\\\47.8 = \frac{100 X 180}{W+180}\\ \\47.8W + 47.8 X 180 = 18000\\47.8W = 18000 - 8604\\W = \frac{9396}{47.8}\\ W = 196.56g$

Therefore, weight of the beam is 196.56g

3.

Total length, L = 100cm

Center of mass, x = 50.8 cm

Position weight placed from fulcrum, y = 9.8cm

Weight of Beam, W = 72.3g

Added weight, F = ?

$50.8 = \frac{100}{\frac{72.3}{F}+1 }\\\ 50.8 = \frac{100}{\frac{72.3+F}{F} } \\\\50.8 = \frac{100 X F}{72.3+F}\\ \\50.8 X 72.3 + 50.8 X F = 100F\\\\3672.84 = 100F-50.8F\\3672.84 = 49.2F\\F = 74.65g$

Therefore, Added weight F is 74.65g

A = 59.35cm

B = 196.56g

C = 74.65g

4 0

3 years ago

Arthur is testing how well various types of disinfectants can kill E. coli bacteria. He starts with a Petri dish that is covered

maw [93]

The variable is the disinfectant that is used, because there different ones being used

3 0

3 years ago

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A 4.50-volt personal stereo uses 1950 joules of electrical energy in one hour. what is the electrical resistance of the personal

saveliy_v [14]

The stereo uses an energy of $E=1950 J$ in a time $t=1 h=3600 s$ , therefore the power of the stereo is given by
$P= \frac{E}{t}= \frac{1950 J}{3600 s}=0.54 W$

We also know that the power of an electrical device is related to its voltage, V, and its resistance, R, by the following equation
$P= \frac{V^2}{R}$
therefore, we can rearrange the equation to calculate the resistance of the stereo:
$R= \frac{V^2}{P}= \frac{(4.5 V)^2}{0.54 W}=37.5 \Omega$

6 0

4 years ago

An object becomes charged when the atoms in the object gain or lose. True or False

sp2606 [1]

Answer:

True.

Explanation:

When an object's atoms gain or lose electrons, it becomes an ion, becoming charged.