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2 years ago

The sun appears to move through the background stars. This apparent motion would not exist if:_________.

Physics

1 answer:

otez555 [7]2 years ago

3 0

Answer:

b) the earth did not orbit the sun

Explanation:

The sun appears to move through the background stars due to parallax . Parallax is a phenomenon when the near object appears to move faster than the distant object . If we travel in a train , the near object like electric poles on rail track or trees and fields nearby appear to move faster against the distant background .

Hence when the earth moves around the sun , the sun appears to move against the background the stars which are far away . Had earth remained stationary at a place on its orbit around the sun , the sun would have appeared stationary against the background the stars .

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3 years ago

Find the ratio of intensities in 4 different sets of red to violet spectral satellites in Raman scattering spectra of CCl4 molec

Vlad1618 [11]

Complete Question

Find the ratio of intensities in 4 different sets of red to violet spectral satellites in Raman scattering spectra of CCl4 molecules at T=27C temperature if corresponding resonant infrared frequencies (equivalent to frequencies of nuclei vibrations) of CCl4 molecule are 217, 315, 457 and 774 cm-1 . (Note: Wavenumber N in cm-1 is defined as $N=1/\lambda\ cm^{-1}$ )

Answer:

The ratio of intensities is $I_1 : I_2 : I_3 : I_4 = 217 : 315 : 457 : 774$

Explanation:

From the question we are told that

The number of sets of satellite is $n = 4$

The temperature is $T = 27 ^oC$

The resonant infrared frequencies are $f_1 = 217 cm^{-1}$

$f_2 = 315 cm^{-1}$

$f_3 = 457 cm^{-1}$

$f_4 = 774 cm^{-1}$

From the question we see that the wave number also has a unit of $cm^{-1}$ hence the value of the wave numbers of the molecule are

$N_1 = 217 cm^{-1}$

$N_2 = 315 cm^{-1}$

$N_3 = 457 cm^{-1}$

$N_4 = 774 cm^{-1}$

Generally intensity is mathematically represented as

$I = \frac{nhc}{A \lambda }$

Here we see that I varies inversely with wavelength i,.e

$I \ \ \alpha \ \ \frac{1}{\lambda }$

From the question we are told that the wave number is mathematically represented as

$N = \frac{1}{\lambda }$

Therefore

$I \ \ \alpha \ \ N$

This implies that the ratio of intensity in first set to that of second set to that of third set to that of fourth set is equal to the ratio of the wavenumber in the first set to that of the second set to that of third set to that of fourth

This is mathematically represented as

$I_1 : I_2 : I_3 : I_4 = N_1 : N_2 : N_3 : N_4$

Substituting values

$I_1 : I_2 : I_3 : I_4 = 217 : 315 : 457 : 774$

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