Answer:
FA / FB = 100
Explanation:
given two identical cars
let their initial speed be U m/s
for car 1 let it deaccelerates with a1
0 = U² - 2*a1*(10cm)
a1 = U² / (2*(0.1))
car2 deaccelerates with a2
0 = U² - 2*a2*(10)
a2 = U² / (2*(10))
FA = m*a1
FB = m*a2
FA/FB = a1 / a2
= 10/0.1
= 100
FA/FB = 100
Answer:
The mass of the beam is 0.074 kg
Explanation:
Given;
length of the uniform bar, = 1m = 100 cm
Set up this system with the given mass and support;
0-----------------33cm-----------------------------------100cm
↓ Δ ↓
0.15kg m
Where;
m is mass of the uniform bar
Apply the principle of moment to determine the value of "m"
sum of anticlockwise moment = sum of clockwise moment
0.15kg(33 - 0) = m(100 - 33)
0.15(33) = m(67)
Therefore, the mass of the beam is 0.074 kg
1.8N
Explanation:
Given parameters:
Mass of the hockey puck = 0.15kg
Acceleration = 12m/s²
Unknown:
Net force = ?
Solution:
According newton's second law of motion "the net force on a body is the product of its mass and acceleration".
Force = mass x acceleration
Input the variables;
Net force = 0.15 x 12 = 1.8N
learn more:
Newton's law of motion brainly.com/question/11411375
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Answer:
distance= velocity ×time
distance= 62×10
distance=620m
hope it helps you mate please mark me as brainliast
Answer:
Explanation:
The voltage of a disconnected charged capacitor increases when the plate area is decreased.
When plate area decreases , capacitance C decreases , but charge Q remains constant .
Q = C V where C is capacitance and V is voltage .
when C decreases , V increases for keeping Q constant .
So the statement is true.
The electric field is dependent on the charge density on the plates.
This statement is true .
The voltage of a connected charged capacitor remains the same when the plate area is decreased .
For a connected capacitor , V or voltage is constant which is equal to voltage of charging battery .
So the statement is true .