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Amiraneli [1.4K]
3 years ago
7

Use the principle of superposition (Equation 1.3) to predict the electric field at the point 0.5 meters to the right and 1.5 met

ers above the 5 nC charge. Express your result both in terms of x and y components, and then in terms of total magnitude and direction.
Physics
1 answer:
kvasek [131]3 years ago
4 0

Answer:

Explanation:

The x component of electric field Ex = k Q / R²

= 9 x 10⁹ x 5 x 10⁻⁹ / .5²

= 180 N .

The y component of electric field Ey = k Q / R²

The y component of electric field Ey

= 9 x 10⁹ x 5 x 10⁻⁹ / 1.5²

= 20 N

Total field = \sqrt{180^2+20^2}

= 181.1 N .

Angle with x axis = Tanθ = Ey / Ex = 20 / 180 = .111

= 6.33⁰

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As rotational speed increases, thrust____?
never [62]
Increases exponentially is your correct answer
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2 years ago
What objects has large volume and small mass
viva [34]

Answer:

A hot air balloon

7 0
3 years ago
un motor electric efectueaza un lucru mecanic de 864 j in 0.5 min.tensiunea la bornele sale este de 12v si este parcurs de un cu
GrogVix [38]

Answer:

96%

Explanation:

To find the values of the motor efficiency you use the following formula:

E=\frac{P_o}{P_i}100

P_o: output power = 864J/0.5min=864J/30s=28.8W

P_i: input power = I*V = (3A)(12V) = 36W

By replacing this values you obtain:

E=\frac{28.8W}{30W}*100=96\%

hence, the motor efficiency is about 96%

traslation:

Pentru a găsi valorile eficienței motorului, utilizați următoarea formulă:

P_o: putere de ieșire = 864J / 0.5min = 864J / 30s = 28.8W

P_i: putere de intrare = I * V = (3A) (12V) = 36W

Înlocuind aceste valori obțineți:

prin urmare, eficiența motorului este de aproximativ 96%

3 0
2 years ago
A child throws a ball vertically upward to a friend on a balcony 28 m above him. The friend misses the ball on its upward flight
photoshop1234 [79]

Answer:

t=1.9 sec

Explanation:

From the question we are told that:

Height h=28m

Time t=3s

Generally the Newton's equation for Initial velocity upward is mathematically given by

 s=ut+\frtac{1}{2}at^2

 28=3u-\frac{1}{2}*9.8*3^2

 u=24.03m/s

Generally the velocity at  elevation and depression occurs  as ball arrives and passes through S=28

 v=\sqrt{24.03-2*9.8*28}

 v=5.35m/s and -5.35m/s

Generally the Newton's equation for time to reach initial velocity  is mathematically given by

 v=u+at

 5.35=24.03-9.8t

 t=\frac{28.03-5.35}{9.8}

 t=1.9 sec

4 0
2 years ago
Apply the general results obtained in the full analysis of motion under the influence of a constant force in Section 2.5 to answ
zvonat [6]

Answer:

y(i) = h

v(y.i) = 0

Explanation:

See attachment for elaboration

3 0
2 years ago
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