1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
trasher [3.6K]
3 years ago
10

The image shows the positions of a car on a roller coaster track. Arrange the cars in order based on their gravitational potenti

al energy. Begin with the lowest potential energy and end with the highest.
A B C D E

Physics
2 answers:
RideAnS [48]3 years ago
5 0

Correct order, from lowest potential energy to highest potential energy:

E - C - D - B - A

Explanation:

The gravitational potential energy of the car is given by:

U=mgh

where

m is the car's mass

g is the gravitational acceleration

h is the height of the car relative to the ground

In the formula, we see that m and g are constant, so the potential energy of the car depends only on its height above the ground, h. The higher the car from the ground, the larger its potential energy. Therefore, the position with least potential energy will be E, since the height is the minimum. Then, C will have more potential energy, because the car is at higher position, and so on: the position with greatest potential energy is A, because the height of the car is maximum.

larisa [96]3 years ago
3 0

Answer:

E,C,D,B,A

Explanation:

You might be interested in
In a heat engine if 1000 j of heat enters the system the piston does 500 j of work, what is the final internal energy of the sys
nydimaria [60]

Answer : The final energy of the system if the initial energy was 2000 J is, 3500 J

Solution :

(1) The equation used is,

\Delta U=q+w\\\\U_{final}-U_{initial}=q+w

where,

U_{final} = final internal energy

U_{initial} = initial internal energy

q = heat energy

w = work done

(2) The known variables are, q, w and U_{initial}

initial internal energy = U_{initial} = 2000 J

heat energy = q = 1000 J

work done = w = 500 J

(3) Now plug the numbers into the equation, we get

U_{final}-(2000J)=(1000J)+(500J)

(4) By solving the terms, we get

U_{final}-(2000J)=(1000J)+(500J)

U_{final}-(2000J)=1500J

U_{final}=2000J+1500J

U_{final}=3500J

(5) Therefore, the final energy of the system if the initial energy was 2000 J is, 3500 J

5 0
3 years ago
A car passes you at 18 m/s to the north and increases its speed at a rate of 3.0 m/s. Determine the car's velocity when it has a
monitta

122

...................................................................,.......,..................................

8 0
3 years ago
A curve that has a radius of 90 m is banked at an angle of =10.8∘. If a 1100 kg car navigates the curve at 75 km/h without skidd
PilotLPTM [1.2K]

The minimum coefficient of static friction  between the pavement and the tires is 0.69.

The given parameters;

  • <em>radius of the curve, r = 90 m</em>
  • <em>angle of inclination, θ = 10.8⁰</em>
  • <em>speed of the car, v = 75 km/h = 20.83 m/s</em>
  • <em>mass of the car, m = 1100 kg</em>

The normal force on the car is calculated as follows;

F_n = mgcos(\theta)

The frictional force between the car and the road is calculated as;

F_k = \mu_k F_n\\\\F_k = \mu_k mgcos(\theta)

The net force on the car is calculated as follows;

mgsin(\theta) +  \mu_s mgcos(\theta) = \frac{mv^2}{r} \\\\mg(sin\theta \ + \ \mu_s cos\theta)= \frac{mv^2}{r} \\\\g(sin\theta \ + \ \mu_s cos\theta)= \frac{v^2}{r}\\\\sin\theta \ + \ \mu_s cos\theta = \frac{v^2}{rg}\\\\\mu_s cos\theta = sin\theta \  + \ \frac{v^2}{rg}\\\\\mu_s = \frac{sin\theta}{cos \theta} + \frac{v^2}{cos (\theta)rg}\\\\\mu_s = tan(\theta) +   \frac{v^2}{cos (\theta)rg}\\\\\mu_s = tan(10.8) +  \frac{(20.83)^2}{cos(10.8) \times 90 \times 9.8} \\\\\mu_s = 0.19 + 0.5\\\\

\mu_s = 0.69

Thus, the minimum coefficient of static friction  between the pavement and the tires is 0.69.

Learn more here:brainly.com/question/15415163

8 0
3 years ago
Which part of the electronic system of a tape player would be different from that of a record player?
Luda [366]

Answer:

In a tape player sound is stored in the tape then from the tape,sound is converted to electrical signals then to the ears where as in a record player electric signals from the spinning cord are feed directly into an amplifier connected to a loudspeaker for us to hear.

Explanation:

In a record player, magnetic devices convert sound vibrations originating from from a spinning record into electric signals that are feed into an amplifier in a loudspeaker to make us hear the sound.A tape player utilizes a magnetic tape as the medium where the sound is stored into the tape.Here sound waves are converted into electric signals in the recorded and the sound wave goes to our ears due to polarity changes caused by the small magnets in the headphones.

5 0
3 years ago
What does the band of stability for atomic nuclei refer to
Irina18 [472]

Explanation:

Band of stability for atomic nuclei refer to a narrow region in the graph of number of neutrons to the number of protons for stable nuclei. It is the band of nuclei stability.

We know that radioactive elements achieve stability be ejecting nucleons( neutrons and protons). The regions( combination of number of neutrons and protons) in which the nucleus is most is called band of stability.

5 0
3 years ago
Other questions:
  • What most likley happens to the air at the beach at night
    7·2 answers
  • the public is not yet able to purchase hydrogen fuel cell powered cars because engineers have to determine
    9·1 answer
  • What is the structure of a magnet?
    11·1 answer
  • The angular quantities: angular displacement, angular velocity, angular acceleration, are defined in a very similar way to the l
    7·1 answer
  • Describe the difference between potencial and kinetic energy
    5·1 answer
  • What is the frequency of a wave that has a wavelength of 20 cm and a speed of 10 m/s
    8·1 answer
  • What do these compounds have in common H2O cl2 NH3
    7·1 answer
  • 10. At point A, a runner is jogging 5 m/s. Forty seconds later, at point B
    13·1 answer
  • A factory line moves parts for an automobile at a constant speed of 0.22 m/s. How long does it take the parts to move 8.5 m alon
    15·1 answer
  • The car's initial speed was 32m / s and it takes 99 seconds for the car to come to a full stop after the driver applies the brak
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!