Question

Light of wavelength 600 nm passes though two slits separated by 0.25 mm and is observed on a screen 1.4 m behind the slits. The location of the central maximum is marked on the screen and labeled y = 0.
At what distance, on either side of y = 0, are the m = 1 bright fringes ?

Answer 1

Answer:

y = 3.36 mm

Explanation:

The wavelength of the light, $\lambda = 600 nm= 600 * 10^{-9} m$

Separation between the two slits, d = 0.25 mm

$d = 0.25 * 10^{-3} m$

The separation between the light image and the screen, L = 1.4 m

m = 1

the distance of the bright fringes from the central maximum, $y = \frac{m \lambda L}{d}$

$y = \frac{1 * 600 * 10^{-9} }{0.25 * 10^{-3} }$

y = 0.00336 m

y = 3.36 mm

Answer 2

Answer:

y(m=+1,-1)=3.36mm

Explanation:

We have to take into account the expression for the position of the fringes

$y=\frac{m\lambda D}{d}$

Where lambda is the wavelength of the light, D is the distance to the screen, m is the order of the fringe and d is the distance between slits.

By replacing we have

$y=\frac{(1)(600*10^{-9}m)(1.4m)}{0.25*10^{-3}m}=3.36*10^{-3}m$

There is a distance of 3.36mm to the secon maximum in the screen.

HOPE THIS HELPS!!