Atomic mass of F: 19.0 g/mol
Atomic mass of S: 32.1 g/mol
1.18 g F = [1.18 g / 19.0 g / mol] = 0.062 mol F
1 g S = 1 g/ 32.1 g/mol = 0.031 mol S
Divide by 0.031
0.062 mol F / 0.031 = 2 mol F
0.031 mol S / 0.031 = 1 mol S
SF2 Then X = 2
Verification:
F2 = 2*19.0 g = 38 g F
S = 32.1 g
36 gF / 32.1 g S = 1.18 g F / g S
Pure substance element I think
The answers this question is A.
Explanation:
From the knowledge of law of multiple proportions,
mass ratio of S to O in SO:
mass of S : mass of O
= 32 : 16
= 32/16
= 2/1
mass ratio of S to O in SO2:
= mass of S : 2 × mass of O
= 32 : 2 × 16
= 32/32
= 1/1
ratio of mass ratio of S to O in SO to mass ratio of S to O in SO2:
= 2/1 ÷ 1/1
= 2
Thus, the S to O mass ratio in SO is twice the S to O mass ratio in SO2.
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Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.
Elements form bonds to increase their stability. The main types of bonds are:
- Metallic bonds: they are formed between metals and the electrons are in a delocalized cloud.
- Ionic bonds: they are formed between metals (lose electrons) and nonmetals (gain electrons)
- Covalent bonds: they are formed between nonmetals, which share electrons.
Regarding the bonds in FesO₄:
- Fe is a metal and S a nonmetal, thus they will form ionic bonds.
- S and O are both nonmetals, thus they will form covalent bonds.
Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.
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