1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lyrx [107]
3 years ago
12

A) At a certain instant, a particle-like object is acted on by a force F = (3.0 N) ihat - (3.0 N) jhat + (9.0 N) khat while the

object's velocity is v = - (2.0 m/s) ihat + (4.0 m/s) khat. What is the instantaneous rate at which the force does work on the object?
(b) At some other time, the velocity consists of only a j component. If the force is unchanged, and the instantaneous power is -12 W, what is the velocity of the object just then?
Physics
1 answer:
Paha777 [63]3 years ago
4 0

Answer:

a) Instantaneous rate at which the force does work on the object = -6 W

b) \texttt{Velocity of object,}\vec{v}=4\hat{j}

Explanation:

a) Given that

             \vec{F}=3\hat{i}-3\hat{j}

   and

            \vec{v}=-2\hat{i}+4\hat{k}

Instantaneous rate at which the force does work on the object is called power.

          Power is the dot product of force and velocity.

          P=\vec{F}.\vec{v}=(3\hat{i}-3\hat{j}).(-2\hat{i}+4\hat{k})=-6W

Instantaneous rate at which the force does work on the object = -6 W

b) Here given that    \vec{v}=-a\hat{j}

  Power = -12 W

  P=\vec{F}.\vec{v}=(3\hat{i}-3\hat{j}).a\hat{j}=-12W\\\\-3a=-12\\\\a=4\\\\\vec{v}=4\hat{j}

\texttt{Velocity of object,}\vec{v}=4\hat{j}

You might be interested in
Listed in the Item Bank are some important labels for sections of the image below. To find out more information about labels, so
erica [24]

1 - cytoplasm

2 - DNA

3 - rybosome

4 - cell membrane

5 - nucleus

5 0
3 years ago
A 1.0 kilogram ball is thrown into the air with an initial velocity of 30m/s. How much kinetic energy does the ball have? (B) ho
Gala2k [10]

Answer:

450 joules ; 450 joules ; 45.9 m

Explanation:

Given that :

Initial Velocity, u = 30m/s

Mass, m = 1 kg

Kinetic Energy of ball (KE) = 0.5mu²

K. E = 0.5 * 1 * 30^2

K.E = 0.5 * 900

K.E = 450 Joules

B.) Potential Energy (P. E)

P. E = mgh

At the highest point, all kinetic energy has would have become potential energy, hence

K. E = P. E = 450 Joules

C) Height of the ball :

From ; P. E = mgh

Where ; g = acceleration due to gravity = 9.8m/s² ; h = height

450 = 1 * 9.8 * h

450 = 9.8h

h = 450 / 9.8

h = 45.918

h = 45.9 m

7 0
3 years ago
An inductor is connected to the terminals of a battery that has an emf of 16.0 V and negligible internal resistance. The current
balu736 [363]

Answer:

(a) The resistance R of the inductor is 2480.62 Ω

(b) The inductance L of the inductor is 1.67 H

Explanation:

Given;

emf of the battery, V = 16.0 V

current at 0.940 ms = 4.86 mA

after a long time, the current becomes 6.45 mA = maximum current

Part (a) The resistance R of the inductor

R = \frac{V}{I_{max}} = \frac{16}{6.45*10^{-3}} = 2480.62 \ ohms

Part (b)  the inductance L of the inductor

\frac{Rt}{L} = -ln(1-\frac{I}I_{max}})\\\\L = \frac{Rt}{-ln(1-\frac{I}I_{max})}}

where;

L is the inductance

R is the resistance of the inductor

t is time

L = \frac{Rt}{-ln(1-\frac{I}I_{max})}} = \frac{2480.62*0.94*10^{-3}}{-ln(1-\frac{4.86}{6.45})} \\\\L =\frac{2.3318}{1.4004} = 1.67 \ H

Therefore, the inductance is 1.67 H

5 0
3 years ago
Renee looks out a window. The window is clear, or transparent. This means most of the light that hits the window is:
Mrrafil [7]
My answer d absorbed
5 0
3 years ago
Read 2 more answers
Two forces F1 and F2 of equal magnitude are applied to a brick of mass 20kg lying on the floor as shown in the figure above. If
jeka57 [31]

Let F_{1}=F_{2}=F.

Normal force equals (using Newton's third law) N=mg+F\sin30^{o}-F\sin37^{o}.

F_{f}\leq \mu N = \mu(mg+F\sin30^{o}-F\sin37^{o}), but F_{f}\leq F(\cos30^o+\cos37^o) for all F_{f} (in order to start moving the break). Therefore F(\cos 30^o+\cos37^o)\geq \mu(mg+F\sin30^{o}-F\sin37^{o}), solving for F: F\geq \frac{\mu mg}{\cos30^o+\cos37^o-\mu\sin30^o+\mu\sin37^o}\approx 46,91\; \textbf{N}

7 0
3 years ago
Other questions:
  • If the slope of a line on a speed-time graph is 0 and it is not on the x-axis, what is the object doing?
    9·1 answer
  • Springfield's "classic rock" radio station broadcasts at a frequency of 102.1 mhz. what is the length of the radio wave in meter
    14·1 answer
  • What can be defined as the rate at which velocity changes
    10·2 answers
  • Variations in the resistivity of blood can give valuable clues about changes in various properties of the blood. Suppose a medic
    13·1 answer
  • Please need help on this
    15·1 answer
  • A car traveling at 26 m/s starts to decelerate steadily. It comes to a complete stop in 13 seconds. What is its acceleration?
    10·1 answer
  • A snail crawls 300 cm in 1 hour. Calculate the snail's speed in each of the following units. a. centimeters per hour (cm/h) b. c
    10·1 answer
  • A car has a kinetic energy of 103kJ.
    10·1 answer
  • The room temprature (25 C) fats in unsaturated fatty acids are <br>​
    9·2 answers
  • True or False?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!