1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lyrx [107]
3 years ago
12

A) At a certain instant, a particle-like object is acted on by a force F = (3.0 N) ihat - (3.0 N) jhat + (9.0 N) khat while the

object's velocity is v = - (2.0 m/s) ihat + (4.0 m/s) khat. What is the instantaneous rate at which the force does work on the object?
(b) At some other time, the velocity consists of only a j component. If the force is unchanged, and the instantaneous power is -12 W, what is the velocity of the object just then?
Physics
1 answer:
Paha777 [63]3 years ago
4 0

Answer:

a) Instantaneous rate at which the force does work on the object = -6 W

b) \texttt{Velocity of object,}\vec{v}=4\hat{j}

Explanation:

a) Given that

             \vec{F}=3\hat{i}-3\hat{j}

   and

            \vec{v}=-2\hat{i}+4\hat{k}

Instantaneous rate at which the force does work on the object is called power.

          Power is the dot product of force and velocity.

          P=\vec{F}.\vec{v}=(3\hat{i}-3\hat{j}).(-2\hat{i}+4\hat{k})=-6W

Instantaneous rate at which the force does work on the object = -6 W

b) Here given that    \vec{v}=-a\hat{j}

  Power = -12 W

  P=\vec{F}.\vec{v}=(3\hat{i}-3\hat{j}).a\hat{j}=-12W\\\\-3a=-12\\\\a=4\\\\\vec{v}=4\hat{j}

\texttt{Velocity of object,}\vec{v}=4\hat{j}

You might be interested in
The Sun is expected to undergo hydrogen fusion for a total of _____ years. a million 10 million a billion 10 billion 100 billion
Elanso [62]
The correct answer is 10 billion years. The Sun is expected to undergo hydrogen fusion for a total of 10 billion years. The Sun generates its energy by nuclear fusion of hydrogen and produces helium nucleus. It fuses 620 million metric tons every second.
3 0
3 years ago
Read 2 more answers
A combination lock has a 1.3-cm-diameter knob that is part of the dial you turn to unlock the lock. To turn that knob, you twist
galina1969 [7]

Answer:

0.04225 Nm

Explanation:

N = Force applied = 5 N

\mu = Coefficient of static friction = 0.65

d = Diameter of knob = 1.3 cm

r = Radius of knob = \frac{d}{2}=\frac{1.3}{2}=0.65\ cm

Force is given by

F=N\mu\\\Rightarrow F=5\times 0.65\\\Rightarrow F=3.25\ N

When we multiply force and radius we get torque

Torque on thumb

\tau_t=F\times r\\\Rightarrow \tau_t=3.25\times 0.0065\\\Rightarrow \tau_t=0.021125\ Nm

Torque on forefinger

\tau_f=F\times r\\\Rightarrow \tau_f=3.25\times 0.0065\\\Rightarrow \tau_f=0.021125\ Nm

The total torque is given by

\tau=\tau_t+\tau_f\\\Rightarrow \tau=0.021125+0.021125\\\Rightarrow \tau=0.04225\ Nm

The most torque that exerted on the knob is 0.04225 Nm

4 0
3 years ago
Juanita made an electromagnet by placing an iron bar inside a coil of wire and then running current through the wire. After awhi
swat32

Answer: Correct Ans is B

Explanation:

5 0
3 years ago
7. A toy car of mass 1.2 kg is driving vertical circles inside a hollow cylinder of radius 2.0m. It is moving at a constant spee
wlad13 [49]

Answer:

a)

N_{top}=9.8N\\N_{bottom}=33.4N

b) v_{min}=4.4m/s

Explanation:

The net force on the car must produce the centripetal acceleration necessary to make this circle, which is a_{cp}=\frac{v^2}{R}. At the top of the circle, the normal force and the weight point downwards (like the centripetal force should), while at the bottom the normal force points upwards (like the centripetal force should) and the weight downwards, so we have (taking the upwards direction as positive):

-m\frac{v^2}{R}=-N_{top}-mg\\m\frac{v^2}{R}=N_{bottom}-mg

Which means:

N_{top}=m\frac{v^2}{R}-mg=(1.2kg)\frac{(6m/s)^2}{2m}-(1.2kg)(9.8m/s^2)=9.8N\\N_{bottom}=m\frac{v^2}{R}+mg=(1.2kg)\frac{(6m/s)^2}{2m}+(1.2kg)(9.8m/s^2)=33.4N

The limit for falling off would be N_{top}=0, so the minimum speed would be:

0=m\frac{v_{min}^2}{R}-mg\\v_{min}=\sqrt{Rg}=\sqrt{(2m)(9.8m/s^2)}=4.4m/s

3 0
3 years ago
What is her initial acceleration if she is initially stationary and wearing steel-bladed skates that point in the direction of?
madreJ [45]
We will apply the Newton's second Law so the we will be able to find the acceleration.
F (tot) = ma
a = F(tot) /  m
a = 32.0 N / 65.0 kg = 0.492 m/s^2
Approximately 0.492 m/s^2 is her initial acceleration if she is initially stationary and wearing steel-bladed skates.

7 0
3 years ago
Other questions:
  • What golf skill should you be working on as a beginner golfer ?
    5·2 answers
  • Tech A says motor action occurs through the interaction of the magnetic fields of the field coils and the armature, which causes
    7·1 answer
  • Light of wavelength 660 nm passes through two narrow slits 0.65 mm apart. The screen is 2.55 m away. A second source of unknown
    12·1 answer
  • A physics department has a Foucault pendulum, a long-period pendulum suspended from the ceiling. The pendulum has an electric ci
    10·1 answer
  • Fill in the blank.
    12·2 answers
  • Describe Lenz's law.
    11·1 answer
  • Is it First or Second law Newtons law? Fill in the blanks
    12·2 answers
  • How does the height of a ramp affect the distance that a toy car will travel?
    10·1 answer
  • Difference between load and effort​
    8·1 answer
  • The force shown in the figure(Figure 1) moves an object from x = 0 to x = 0.75 m.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!