Answer:
I think a is the best answer. but really I can not confirm that.sorry for that.
Answer:
The Lewis structure for the sulfate ion consists of a central sulfur atom with four single bonds to oxygen atoms. This yields the expected total of 32 electrons. Since the sulfur atom started with six valence electrons, two of the S-O bonds are coordinate covalent.
Explanation:
Then that means it has both.
Destructive interference in which waves cancel each other out is depicted in region X,Y and Z.
<u>Explanation:</u>
Interface is the particle property of light waves. When incident light beam is made to pass through holes, the waves will combine either constructively or destructively. Constructive interference means the waves having same phase will get added so they will increase in amplitude. While destructive interference means the waves combining have different phases like crests and troughs. So they undergo decrease or complete vanishing of amplitude.
When waves combine in constructive interference, they form bright white light and when they combine in destructive interference, they form dark black light. So the regions X, Y and Z are shown as dark black colors in the diagram, so these regions represent destructive interference in which waves cancel each other out.
Answer:
Phosphorus
Explanation:
In given diagram there are 15 electrons are present. Which means it is orbital diagram of phosphorus.
The atomic number of phosphorus = 15
Number of electrons = 15
Electronic configuration of phosphorus:
P₁₅ = 1s² 2s² 2p⁶ 3s² 3p³
All other options are incorrect because:
Calcium have 20 electrons.
Electronic configuration of Ca:
Ca₂₀ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
Hydrogen have one electron.
Electronic configuration of H.
H₁ = 1s¹
Magnesium have 12 electrons:
Electronic configuration of Mg:
Mg₁₂ = 1s² 2s² 2p⁶ 3s²
Answer: 0.33M CaBr2
Explanation: Molarity is expressed in moles of solute over liter solution.
M= n solute / L solution
Solution:
First convert mass of CaBr2 to moles using its molar mass
Ca = 40
Br = 80 x 2 answer is 200 g CaBr2.
50.0g CaBr2 x 1 mole CaBr2 / 200 g CaBr2 = 0.25 moles CaBr2
Next convert mL to L
750.0 mL x 1L / 1000mL
= 0.75 L
Substitute the values for M.
M= 0.25 moles CaBr2/ 0.75 L
= 0.33 M CaBr2