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Vlad1618 [11]
3 years ago
12

Which of the following are Arrhenius Bases? A) CH3OH B) CH3COOH C) HOH D) H2NNH2

Chemistry
1 answer:
Viktor [21]3 years ago
4 0
<h3>Answer:</h3>

                  H₂O

Explanation:

                      According to Arrhenius Concept of Acid and Base, "Acid is any specie which when dissolved in water ionizes to produce H⁺ ions".

Examples:

                                  HCl    →    H⁺  +  Cl⁻

                                  H₂SO₄    →    2 H⁺  +  SO₄²⁻

While, "Bases are those species which when dissolved in water produces Hydroxyl Ions (OH⁻)".

Examples:

                                  NaOH    →  Na⁺  +  OH⁻

                                  Mg(OH)₂    →     Mg²⁺  +  2 OH⁻

Given Options:

CH₃OH:

             Methanol when dissolved in water does not dissociate as follow,

                                    CH₃OH     →     H₃C⁺  +  OH⁻

Hence, it does not behave as Arrhenius Base.

CH₃COOH:

                  Acetic acid when dissolved in water produces H⁺ ions and Acetate ions i.e.

                                 CH₃COOH    →    CH₃COO⁻  +  H⁺

Therefore, it can act as Arrhenius Acid instead of Arrhenius Base.

H₂O:

        Water when dissolved in water dissociates as,

                                                  H₂O    →    H⁺  +  OH⁻

As it is producing both H⁺ and OH⁻ ions therefore, it can act as both Arrhenius Base and Arrhenius Acid.

H₂NNH₂:

              Hydrazine when dissolved in water can neither produce OH⁻ ions nor H⁺ ions hence, it is neither Arrhenius Base nor Arrhenius Acid,

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A chemistry student needs 65.0 mL of carbon tetrachloride for an experiment. By consulting the CRC Handbook of Chemistry and Phy
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Answer:

103.3 g

Explanation:

Data Given:

Volume of carbon tetrachloride (v) = 65.0 mL

Density of carbon tetrachloride (d) = 1.59 g/cm³

Solution:

Convert volume of carbon tetrachloride from ml to cm³

1 ml = 1 cm³

so,

65.0 mL = 65.0 cm³

Formula used to calculated mass of carbon tetrachloride should be taken for experiment.

                   d = m/v

Rearrange the above equation:

                   m = d x v . . . . . . .(1)

Put values in equation 1

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