Which of the following does not describe a solid

Fittoniya [83]

the type of energy transferred by a wave in a medium is kinetic energy is true

4 0

3 years ago

The NH₄⁺ ion forms acidic solutions, and the CH₃COO⁻ ion forms basic solutions. However, a solution of ammonium acetate is almos

tigry1 [53]

Not always ammonium salts of weak acids form neutral solutions.

When formic acid reacts with ammonia, ammonium formate is produced:

HCO2H + NH3 ----> NH4HCO2

You already know that the weak conjugate bases of NH3 and HCO2H are NH4+ and HCO2, respectively.

How can the pH of the solution be calculated if the salt's anion causes the pH to rise and the salt's cation causes it to fall? The relative intensities of the basic anion and the acidic cation hold the key to the solution.

As was already established, formate is a weak base and will create hydroxide ions in water, whereas ammonium is a weak acid and will make hydronium ions in water.

NH4⁺ + H2O -----> NH3 + H3O⁺

HCO2⁻ + H2O -----> HCO2H + OH⁻

Since the acid ionization of NH4+ is more favored than the base ionization of HCO2-, the solution will be acidic.

To learn more about ammonium salts:

brainly.com/question/10874844

#SPJ4

6 0

1 year ago

A hydrogen-like ion is an ion containing only one electron. The energies of the electron in a hydrogen-like ion are given by the

yan [13]

Answer:

The ionization energy (in kJ/mol) of the helium ion is 21,004.73 kJ/mol .

Explanation:

$E_n = -(2.18 10-18 J)\times \frac{Z^2}{n^2}$

Z = atomic mass

n = principal quantum number

Energy of the electron in n=1,

$E_1= -(2.18 10^{-18} J)\times \frac{4^2}{1^2}=-3.488\times 10^{-17} J$

Energy of the electron in n = ∞

$E_{\infty}= -(2.18 10^{-18} J)\times \frac{2^2}{\infty ^2}=0 J$

Ionization energy of the $He^+$ ion:

$I.E=E_{infty}-E_1=0-(-3.488\times 10^{-17} J)=3.488\times 10^{-17} J$

$I.E=3.488\times 10^{-20} kJ$

To convert in into kj/mol multiply it with $N_A=6.022\times 10^{23} mol^{-1}$

$I.E=3.488\times 10^{-20} kJ\times 6.022\times 10^{23} mol^{-1}=21,004.73kJ/mol$

3 0

3 years ago

Read 2 more answers

A compound contains nitrogen and a metal. This compound goes through a combustion reaction such that compound X is produced from

tia_tia [17]

Answer:

The correct answer is: X is nitrogen dioxide, and Y is a metal oxide

Explanation:

Combustion of compound of containing nitrogen and metal will give nitrogen dioxide and metal oxide as product. During combustion reaction a compound reacts with oxygen in order to yield oxides of elements present in the compound.

The general equation is given as:

$4M_3N_x+7xO_2\rightarrow 4xNO_2+6M_2O_x$

Hence, the correct answer is :X is nitrogen dioxide, and Y is a metal oxide.

6 0

3 years ago

Write the complete balanced equation for the neutralization reaction that occurs when aqueous hydroiodic acid, HI, and sodium hy

Serhud [2]

Answer:

H+ ( aq ) + HCO3- ( aq ) ------> H2O( l ) + CO2 ( g )

Explanation:

The complete reaction when hydroiodic acid and sodium hydrogen carbonate combine, would be as follows -

HI + NaHCO3 ----> NaI + H2O + CO2

net reaction

H2CO3 is highly unstable, and thus decomposes into the water and carbon dioxide you see present as the reactants. If you didn't know already, H2CO3 is also reffered to as carbonic acid. The rest of the elements present on the reactant side are Iodine and Sodium, which is why they are present on the product side as NaI.

Let me include the " physical states " in this reaction as well -

HI ( aq ) + NaHCO3 ( aq ) ----> NaI ( aq ) + H2O ( l ) + CO2 ( g )

Now the complete ionic equation would simply be each compound present as ions in an aqueous solution, so there is no need for an explanation on this step -

H+ ( aq ) + I- ( aq ) + Na+ ( aq ) + HCO3- ( aq ) -------> Na+ ( aq ) + I- ( aq ) + H2O( l ) + CO2 ( g )

The spectator ions in this reaction are I- and Na+, so canceling them out, you would receive the following net ionic equation -

H+ ( aq ) + HCO3- ( aq ) ------> H2O( l ) + CO2 ( g )

<u><em>Hope that helps!</em></u>

4 0

3 years ago