Answer: Boyle's Law
Explanation:
Boyle's Law which is also called Mariotte's law was formulated by physicist Robert Boyle in 1662.
It posits that the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature.
As the Scuba Diver went deeper, the volume of air dropped so the pressure increased.
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Answer:
Ag+
Explanation:
If you imagine as if the problem were double replacement, you would pair the Cl with one of the following ions provided in the choices. As seen on Table F, Ag+ paired with Cl- produces an insoluble compound, hence the precipitate. All the other ions shown in the multiple choice section, when paired with Cl- will produce a soluble compound, as a result NOT a precipitate.
We may apply a mass balance here. The total moles of NaCl will remain constant before and after the mixing of the solutions. We have three solutions:
1) 25 ml of 5 M NaCl
2) 100 ml of 0 M NaCl
3) A mixture of these solutions with volume 125 ml and concentration C
The moles of a substance are equal to the product of the concentration and volume. Thus:
25 * 5 + 100 * 0 = 125 * C
C = 1 M
The concentration of the final solution is 1 M.
Answer:
2.318032g
Explanation:
-The electrolysis equation of water is written as below:
![2H_2O_{(l)}->2H_2_{(g)}+O_2_{(g)}](https://tex.z-dn.net/?f=2H_2O_%7B%28l%29%7D-%3E2H_2_%7B%28g%29%7D%2BO_2_%7B%28g%29%7D)
-The mole ratio of Water to the hydrogen formed is 1:1, therefore 2.3 moles of hydrogen gas is produced.
-Hydrogen's molar mass is 1.00784 grams:
![Mass=moles\times molar \ mass\\\\\=2.3\times 1.00784\\\\=2.318032\ g](https://tex.z-dn.net/?f=Mass%3Dmoles%5Ctimes%20molar%20%5C%20mass%5C%5C%5C%5C%5C%3D2.3%5Ctimes%201.00784%5C%5C%5C%5C%3D2.318032%5C%20g)
Hence, 2.318032 grams of hydrogen is produced.
The classification of it being a metal, nonmetal, or metalliod will be useful in the process of elimination to determine what it is. Then for the second test, meauring the atomin radius will narrow it down quicker to the mystery elemet's name.
Since you determined what part of the periodic table it's on, then when measuring the atomic radius, you should be able to pinpoint what the element is more surely.