For every 1 mole of C6H12O6, you need 6 moles of water. Multiply the 2.5 moles you are trying to make by the 6 of water you need, and 4) 15 is your answer.
Answer:
Use pOH = -log₁₀ [OH-]
Explanation:
pOH can be calculated from the concentration of hydroxide ions using the formular below:
pOH = -log₁₀ [OH-]
The pOH is the negative logarithm of the hydroxide ion concentration.
Answer:
If a body is accelerated by 10m/s^2, it means that the body's speed (or velocity to be precise) is increasing by 10m/s every second. That is, if the initial ...
Answer:
0.558 M
Explanation:
Data obtained from the question. This includes the following:
Initial concentration (C1) =..?
Initial volume (V1) = 25mL
Final volume = 25 + 50 = 75mL
Final concentration (C2) = 0.186 M
The initial concentration of the solution can be obtained as follow:
C1V1 = C2V2
C1 x 25 = 0.186 x 75
Divide both side by 25
C1 = (0.186 x 75) /25
C1 = 0.558 M
Therefore, the initial concentration of the stock was 0.558 M
