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Answer:
%Open the file.
fID = fopen('parts_inv.dat');
%Read from the file.
data = fscanf(fID,'%d\t%f\t%d',[3,inf]);
%Close
fclose(fID);
%Restore the data.
data = data';
%Get the size
[rs, cs] = size(data);
%Set value.
invCost = 0;
%Loop
for rw = 1 : rs
%Find cost
invCost = invCost + (data(rw, 2) * data(rw, 3));
%Loop end
end
%Display the cost.
fprintf('Total cost: %4.2f\n\n', invCost);
Explanation:
Answer:
20m per sec
Explanation:
40÷ 2 = 20 which is your acceleration per sec
Answer:
ωf = 4.53 rad/s
Explanation:
By conservation of the angular momentum:
Ib*ωb = (Ib + Ic)*ωf
Where
Ib is the inertia of the ball
ωb is the initial angular velocity of the ball
Ic is the inertia of the catcher
ωf is the final angular velocity of the system
We need to calculate first Ib, Ic, ωb:
ωb = Vb / (L/2) = 16 / (1.2/2) = 26.67 m/s
Now, ωf will be:
Answer:
Explanation:
The centripetal acceleration of an object in circular motion is the acceleration with which the object is attracted towards the center of the circular orbit. Mathematically, it is given by
where
v is the speed of the object
r is the radius of the orbit
The speed of the object is also given by the ratio between the circumference of the orbit and the orbital period, T:
Substituting into the previous equation, we find a new expression for the centripetal acceleration:
In this problem:
- The radius of the orbit of the Moon is
- The period of the orbit is
Therefore, the centripetal acceleration is: