v₀ = initial speed of the object = 8 meter/second
v = final speed of the object = 16 meter/second
t = time taken to increase the speed = 10 seconds
d = distance traveled by the object in the given time duration = ?
using the kinematics equation
d = (v + v₀) t/2
inserting the above values in the above equation
d = (16 + 8) (10)/2
d = 120 meter
Answer:
what is heat and transfer
Answer:
0.8726
Explanation:
We are to convert 1.85 x to
First, let us convert the numerator from ft3 to m3
1 ft3 = 0.0283 m3
Hence,
1.85 x ft3 = 1.85 x x 0.0283 m3
= 52.355 m3
Now, let us convert the denominator from minutes to seconds
1 min = 60 sec
Therefore;
1.85 x = 52.355/60
= 0.8726
Answer:
The approximate change in entropy is -14.72 J/K.
Explanation:
Given that,
Temperature = 22°C
Internal energy
Final temperature = 16°C
We need to calculate the approximate change in entropy
Using formula of the entropy
Where, = internal energy
T = average temperature
Put the value in to the formula
Hence, The approximate change in entropy is -14.72 J/K.
Answer:
Centripetal Acceleration 18.75 m/s^2, Rotational Kinetic Energy 843.75 J
Explanation:
a Linear acceleration (we cant find tangential acceleration with the givens so we will find centripetal)
a= ω^2*r
ω= 300rev/min
convert into rev/s
300/60= 5rev/s
a= 18.75m/s^2
b) use Krot= 1/2 Iω^2
plug in gives
1/2(30*2.25)(25)= 843.75 J