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4 years ago

13

Through (5,-2) and (-4,-3)

1 answer:

Lapatulllka [165]4 years ago

4 0

I dont know if this helps (sorry its messy) but I tried

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Liam has bought 48 feet of fencing that he will use to build a pig pen. List 6 different dimensions he could create for his pen

Reptile [31]

I assume, that this pen is rectangular.

Look, that 48 = 24 * 2 = 12 * 2 * 2 = 3 * 2 * 2 * 2 * 2
And know choose these numbers and multiply!

First dimension: 3*2 x 2*2*2 = 6 x 8
Second: 3 x 2*2*2*2 = 3 x 16
Third: 3*2*2 x 2*2 = 12 x 4
Fourth: 3*2*2*2 x 2 = 24 x 2
Fifth: 48 x 1
Sixth dimension cannot be integer. So you can for example save this as
48 = 3 * 16 = 1.5 * 2 * 16 = 1.5 * 32

Sixth dimension: 1.5 x 32

NOTE: each dimensions are in feet!

6 0

3 years ago

Simplify the expression (3+i)(2+i)

vovikov84 [41]

Answer:

Step-by-step explanation:

hello :

(3+i)(2+i) = 6+3i+2i+i² but : i² = -1

(3+i)(2+i) = 5+5i

3 0

3 years ago

Read 2 more answers

What is 8|x+2|−6=5|x+2|+3

Liula [17]

Answer:

8|x+2|-6 = 5|x+2|+3

x = -5 or x = 1

3 0

3 years ago

Instructions: Use a graphing calculator to approximate the zeros and vertex of the following quadratic functions. Round to one d

Juli2301 [7.4K]

Using a graphing calculator, we can see the graph of the function y = x²-4x+1:

as we can see, the vertex of the function is (2,-3), and the solutions are (0.3,0) and (3.7,0)

4 0

1 year ago

5. What is the equation of the tangent line to the circle x^2+y^2=1 through the point (6,0)?

notka56 [123]

Answer:

There is no tangent line of the given circle at (6, 0).

Step-by-step explanation:

Given equation of the circle,

$x^2 + y^2 = 1$

∵ equation of a circle is $(x-h)^2 +(y-k)^2 = r^2$ ,

Where, (h, k) is the center of the circle and r is the radius,

By comparing,

Center of the given circle = (0, 0),

Radius of the circle = 1 unit

Now, check whether point (6, 0) lie on the circle,

if x = 6, $6^2 + y^2 = 1$

$36 + y^2 = 1$

$y^2 = 1- 36$

$y= i\sqrt{35}\neq 0$

i.e., (6, 0) does not lie on the circle,

Hence, there is no tangent line of the given circle at (6, 0).

3 0

3 years ago