Answer:
(x, y) = (4, -3)
Step-by-step explanation:
Relative to straight east with angles measured CCW, the vector is ...
5∠-36.9° = 5(cos(-36.9°), sin(-36.9°)) = 5(0.8, -0.6) = (4, -3)
Answer:
The Answer is B
Step-by-step explanation:
A = 8,000(1 + 0.045)12
i just got it right
Answer:
The values of p in the equation are 0 and 6
Step-by-step explanation:
First, you have to make the denominators the same. to do that, first factor 2p^2-7p-4 = \left(2p+1\right)\left(p-4\right)2p
2
−7p−4=(2p+1)(p−4)
So then the equation looks like:
\frac{p}{2p+1}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{5}{p-4}
2p+1
p
−
(2p+1)(p−4)
2p
2
+5
=−
p−4
5
To make the denominators equal, multiply 2p+1 with p-4 and p-4 with 2p+1:
\frac{p^2-4p}{(2p+1)(p-4)}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{10p+5}{(p-4)(2p+1)}
(2p+1)(p−4)
p
2
−4p
−
(2p+1)(p−4)
2p
2
+5
=−
(p−4)(2p+1)
10p+5
Since, this has an equal sign we 'get rid of' or 'forget' the denominator and only solve the numerator.
(p^2-4p)-(2p^2+5)=-(10p+5)(p
2
−4p)−(2p
2
+5)=−(10p+5)
Now, solve like a normal equation. Solve (p^2-4p)-(2p^2+5)(p
2
−4p)−(2p
2
+5) first:
(p^2-4p)-(2p^2+5)=-p^2-4p-5(p
2
−4p)−(2p
2
+5)=−p
2
−4p−5
-p^2-4p-5=-10p+5−p
2
−4p−5=−10p+5
Combine like terms:
-p^2-4p+0=-10p−p
2
−4p+0=−10p
-p^2+6p=0−p
2
+6p=0
Factor:
p=0, p=6p
Answer: There are 32 pints of first type and 128 pints of second type in mixture.
Step-by-step explanation:
Since we have given that
Percentage of pure fruit juice in first type = 60%
Percentage of pure fruit juice in second type = 85%
Percentage of pure fruit juice in mixture = 80%
We will use "Mixture and Allegation" to find the ratio of first and second type in mixture:
First type Second type
60% 85%
80%
------------------------------------------------------------------------
85-80 : 80-60
5% : 20%
1 : 4
so, the ratio of first and second type is 1:4.
Total number of pints of mixture = 160
Number of pints of mixture of first type in mixture is given by

Number of pints of mixture of second type in mixture is given by

Hence, there are 32 pints of first type and 128 pints of second type in mixture.
Given:
The graph of a line segment.
The line segment AB translated by the following rule:

To find:
The coordinates of the end points of the line segment A'B'.
Solution:
From the given figure, it is clear that the end points of the line segment AB are A(-2,-3) and B(4,-1).
We have,

Using this rule, we get


Similarly,


Therefore, the endpoint of the line segment A'B' are A'(2,-6) and B'(8,-4).