False, Because there is some cases where enlarged image needed.
Answer:
A light emitting diode (a semiconductor diode which glows when voltage is applied.
Answer:
Explanation:
Normal length of spring = 28.3 cm
stretched length of spring = 38.2 cm
length of extension = 38.2 - 28.3 = 9.9 cm
= 9.9 x 10⁻² m
force applied to stretch = .55 x 9.8 ( mg )
= 5.39 N
Force constant = force applied / extension
= 5.39 / 9.9 x 10⁻²
= .5444 x 10² N /m
= 54.44 N/m
By conservation of momentum, the initial recoil speed of the
rifle is:
u = 904kg * 0.0106 kg / 3.53 kg = 2.7146 m/s
The final recoil speed v is zero in a distance of d = 0.0346 m
So the rifle's acceleration is a = (0 - u^2) / 2*d = -2.7146^2 / 2*.0323
m/s^2
a = -114.07m/s^2
The work done if the forklift is operating at full capacity is 11,900 J.
We have to recall that power is defined as the rate of doing work. The rate of doing work is defined as;
Power = Work done/time taken
When;
Power = 4950 W
Time taken = 2.40 s
Work done = Power × time taken
Work done = 4950 W × 2.40 s
Work done = 11,900 J
Learn more about work done: brainly.com/question/3902440
