3 years ago

PLZ HELP MEEEEEEEEE ASAP

Physics

1 answer:

mafiozo [28]3 years ago

6 0

The answer is “Impulse acting on it” according to the impulse-momentum theorem.

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Percent error can be reduced by improving both your accuracy and precision.

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g A 1.45-kg block is pushed against a vertical wall by means of a spring (k = 860 N/m). The coefficient of static friction betwe

olga_2 [115]

Answer:

The minimum compression is $x= 0.046m$

Explanation:

From the question we are told that

The mass of the block is $m_b = 1.45 kg$

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The coefficient of static friction is $\mu = 0.36$

For the the block not slip it mean the sum of forces acting on the horizontal axis is equal to the forces acting on the vertical axis

Now the force acting on the vertical axis is the force due to gravity which is mathematically given as

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And the force acting on the horizontal axis is force due to the spring which is mathematically represented as

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Now equating this two formulas and making x the subject

$x = \frac{m_b * g}{k * \mu}$

substituting values we have

$x = \frac{1.45 * 9.8}{860 *0.36}$

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The vertical height of an ocean wave from a crest to a trough is 10 meters. What is the amplitude of the ocean wave?

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The velocity of sound on a particular day outside is 331 meters/second. What is the frequency of a tone if it has a wavelength o

Leya [2.2K]

Answer:
frequency = 5.52 * 10² Hz

Explanation:
the equation that relates velocity, frequency and wavelength is:
velocity = frequency * wavelength

We are given that:
velocity = 331 m/sec
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Substitute with the givens in the equation to get the frequency as follows:
velocity = frequency * wavelength
331 = frequency * 0.6
frequency = 331 / 0.6
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Explanation:

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