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Kitty [74]
3 years ago
5

Which statement is NOT evidence of the plate tectonic theory? PLS SOMEONE HELP QUICK

Physics
1 answer:
alex41 [277]3 years ago
8 0

Answer:

what are the statements?

Explanation:

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A student adds two vectors of magnitudes 48 m and 22 m. What are the maximum and minimum possible values for the resultant of th
Julli [10]

Answer:

<em>Maximum=70 m</em>

<em>Minimum=26 m</em>

Explanation:

<u>Vector Addition </u>

Since vectors have magnitude and direction, adding them takes into consideration not only the magnitudes but also their respective directions. Two vectors can be totally collaborative, i.e., point to the same direction, or be totally opposite. In the first case, the magnitude of the sum is at maximum. Otherwise, it's at a minimum.

Thus, the maximum magnitude of the sum is 48+22 = 70 m and the minimum magnitude of the sum is 48-22= 26 m

4 0
3 years ago
The number of neutrons is equal to the atomic number<br> O A True<br> B. False
jonny [76]

The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus. The number of neutrons is equal to the difference between the mass number of the atom (M) and the atomic number. Therefore, it is true!

6 0
3 years ago
Read 2 more answers
a projectile is lunched with an initial speed of 60.0mm/s at an angle of 30.0° above the horizontal.The projectile lands on a hi
alexandr402 [8]

Answer:

52 mm/s (approximately)

Explanation:

Given:

Initial speed of the projectile is, u=60.0\ mm/s

Angle of projection is, \theta=30.0\°

Time taken to land on the hill is, t=4\ s

In a projectile motion, there is acceleration only in the vertical direction which is equal to acceleration due to gravity acting vertically downward. There is no acceleration in the horizontal direction.

So, the velocity in the horizontal direction always remains the same.

The horizontal component of initial velocity is given as:

u_x=u\cos\theta\\u_x=60\times \cos(30)\\u_x=30\sqrt3\approx52\ mm/s

Now, the velocity in the vertical direction goes on decreasing and becomes 0 at the highest point of the trajectory. So, at the highest point, only horizontal component acts.

Therefore, the projectile's velocity at the highest point of its trajectory is equal to the horizontal component of initial velocity and thus is equal to 52 mm/s.

6 0
3 years ago
Please help it’s do soon
viktelen [127]
When y’all are all over the place and I wanna is a time to come sit in my
8 0
2 years ago
A medicine ball has a mass of 5kg and is thrown with a speed of 3 m/sec what is it's kinetic energy
marissa [1.9K]
KE = 1/2mv^2

KE = 1/2 (5kg)(3m/s)

KE = 22.5 J
8 0
2 years ago
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