Answer:
Attached below
Explanation:
(a) 3-Methylcyclobutene
(b) 1-Methylcyclopentene
(c) 2,3-Dimethyl-2-pentene
(d) (Z)-3-Hexene
(e) (E)-2-Pentene
(f) 3,3,3-Tribromopropene
(g) (Z,4R)-4-Methyl-2-hexene
(h) (E,4S )-4-Chloro-2-pentene
(i) (Z)-1-Cyclopropyl-1-pentene
(j) 5-Cyclobutyl-1-pentene
(k) (R)-4-Chloro-2-pentyne
(l) (E)-4-Methylhex-4-en-1-yne
The structural formula of a compound ( chemical ) is the representation of the molecular structure of the compounds ( i.e. it shows how the atoms in the compound is arranged, also the chemical bonding within the molecules are represented as well.
The correct way to write this number in scientific notation : 6.022 x 10²³
<h3>Further explanation
</h3>
Scientific Notation is a standard form of writing numbers used in mathematical operations
The rules:
1. Writing order : first digit, decimal point, next digit
2. Then followed by powers of 10 (the value can be +/-)
If the value is> 10 (the power of 10 is +), the decimal point is moved to the left, to the right of the first digit
If the value is <10 ((the power of 10 is -), the decimal point is moved to the right, to the right of the first digit
I certainly didn't count the details of the number of zeros listed, but only saw the answer choices.
And the right ones are: 6.022 x 10²³
Answer:
Oxide of manganese, Potassium permanganate, Manganese bromide and manganese oxide.
Explanation:
1. Manganese dioxide
Its chemical formula is 
. It is +4 oxidation state. It is a black solid which is fairly stable.
2. Potassium permanganate
Its chemical formula is 
. It is commonly used in the laboratories as oxidizing agent. They appear black in color.
3 Manganese bromide
Its chemical formula is 
4. Oxides of manganese
Chemical formula is 
The most stable state of Manganese is +2 oxidation state.
Answer:
Empirical formula is C₃H₃O.
Explanation:
Given data:
Mass of compound = 0.519 g
Mass of CO₂ = 1.24 g
Mass of H₂O = 0.255 g
Empirical formula = ?
Solution:
%age of C,H,O
C = 1.24 g/0.519 × 12/44 ×100 = 65.5%
H = 0.255 g/0.519 × 2.016/18 ×100 = 5.6%
O = 100 - (65.5+5.6)
O = 28.9%
Number of gram atoms of H = 5.6 / 1.01 = 5.5
Number of gram atoms of O = 28.9 / 16 = 1.81
Number of gram atoms of C = 65.5 / 12 = 5.5
Atomic ratio:
C : H : O
5.5/1.81 : 5.5/1.81 : 1.81/1.81
3 : 3 : 1
C : H : O = 3 : 3 : 1
Empirical formula is C₃H₃O.
The chemical nature of Q sepharose which allows it to be used as an ion exchanger include the following: It is an insoluble matrix which is in form of micro beads. The bead are porous, which provides a large surface area within and outside them. This properties make it possible for Q sepharose to finely separate different organic molecules.<span />
