Answer:
For proton: 2592 m/s In the same direction of electric field.
For electron: 4752000 m/s In the opposite direction of electric field.
Explanation:
E = 500 N/C, t = 54 ns = 54 x 10^-9 s,
Acceleration = Force /mass
Acceleration of proton, ap = q E / mp
ap = (1.6 x 10^-19 x 500) / (1.67 x 10^-27) = 4.8 x 10^10 m/s^2
Acceleration of electron, ae = q E / me
ae = (1.6 x 10^-19 x 500) / (9.1 x 10^-31) = 8.8 x 10^13 m/s^2
For proton:
u = 0, ap = 4.8 x 10^10 m/s^2, t = 54 x 10^-9 s
use first equation of motion
v = u + at
vp = 0 + 4.8 x 10^10 x 54 x 10^-9 = 2592 m/s In the same direction of electric field.
For electron:
u = 0, ae = 8.8 x 10^13 m/s^2, t = 54 x 10^-9 s
use first equation of motion
v = u + at
vp = 0 + 8.8 x 10^13 x 54 x 10^-9 = 4752000 m/s In the opposite direction of electric field.
