When a copper wire is placed in a beaker containing a solution of silver nitrate(AgNO3), the copper (Cu) will reduce the positive silver ions (Ag+) to metallic silver (Ag). In this same process, Copper (Cu) is oxidized to produce Copper II ions (Cu2+).
The reaction will continue to progress and silver (Ag) crystals will begin to form on the Copper (Cu) wire and thus, we will observe that the solution becomes blue as a result of the formation of copper II (Cu2+) ions.
