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dexar [7]
3 years ago
7

Drop the insta babes :)​

Chemistry
2 answers:
Ksivusya [100]3 years ago
5 0
Okay, I will do it just for you honey
bezimeni [28]3 years ago
3 0
I’m a dude bruv I mean if u into that
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What is the temperature -71 oC expressed in Kelvin?<br> Group of answer choices
satela [25.4K]

Answer: 202.15

Explanation:

-71°C + 273.15

= 202.15K

5 0
3 years ago
When butane burns completely, only water and carbon dioxide gas are produced. If 11.6 g of butane and 40.0 L of oxygen at 22.0o
Angelina_Jolie [31]

19.7 litre volume of carbon dioxide gas at 22.0o C and 102 kPa can be collected over water.

<h3>What is vapour pressure?</h3>

Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.

Moles of Butane = mass in grams / molar mass = 11.6 / 58.12 = 0.2

Volume of O_2 (V) = 40 liter

Temperature (T) = 22°C = 22 + 273 = 295 K

Pressure (P) = 102 kPa = 102 / 101.325 = 1.007 atm

Moles of O_2 (n) can be calculated by ideal gas equation.

PV = nRT

n = 1.007 40 ÷ 0.0821 295 = 1.663

Balanced chemical reaction;

2C_4H_10 + 13O_2 ---> 8CO_2 + 10H_2O

From reaction;

13 moles O_2 require 2 moles C_4H_10

So, 1.663 moles O_2 will require = 2 x 1.663 ÷13 = 0.256 moles of C_4H_10

Thus C_4H_10 is a limiting reagent. So it will drive the yield of CO_2.

Moles of CO_2 produced = (8/2) 0.2 = 0.8 moles

Pressure of CO_2 (P) = 102 - 2.24 = 99.76 kPa = 99.76  ÷ 101.325 = 0.985 atm

Applying the ideal gas equation for CO_2,

PV = nRT

0.985 V = 0.8 0.0821 x 295

V = 19.7 liter

The volume of CO_2 produced = 19.7 liter.

Learn more about the vapour pressure here:

brainly.com/question/25699778

#SPJ1

5 0
1 year ago
The smallest unit of an element that can exist either alone or in combination with other such particles of the same or different
Mekhanik [1.2K]

Answer

im not quite sure but I think the answer is <em>D atom</em><em> </em>

Explaination

5 0
3 years ago
16.6g CaCl2 dissolved in water and completely dissociates. The molality of chloride ions in 300g of water is
vova2212 [387]

Answer:

— The molality of chloride ions in 300g of water is. A) 1.00 molal. B) 0.500 molal. C) 0.0553 molal. D) 0.111 molal.

3 0
2 years ago
How many liters of O2 gas will be produced at STP from 4 moles of KC1O3
quester [9]

Answer:

V = 134.5 L

Explanation:

Given data:

Number of moles of KClO₃ = 4 mol

Litters of oxygen produced at STP = ?

Solution:

Chemical equation:

2KClO₃  →  2KCl   + 3O₂

Now we will compare the moles of KClO₃ with oxygen.

                    KClO₃        :           O₂

                        2            :           3

                        4            ;          3/2×4 = 6 mol

Litters of oxygen at STP:

PV = nRT

V = nRT/P

V = 6 mol × 0.0821 atm.L/mol.K × 273 K / 1atm

V = 134.5 L / 1

V = 134.5 L

5 0
3 years ago
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