Answer:
Magnesium dichloride
HoPe ThIs HeLpS! aNd HaVe A gOoD dAy!
Answer:
SO < CO2 < C3H8
Explanation:
Entropy refers to the degree of disorderliness of a system. The standard molar entropy of a substance refers to the entropy of 1 mole of the substance vunder standard conditions.
The molar entropy depends on the number of microstates in the system which in turn depends on the number of atoms in the molecule.
C3H8 has 11 atoms and hence the highest number of microstates followed by CO2 having three atoms and least of all SO having only two atoms.
We use Charles's Law: V1/T1=V2/T2
Standard Temperature: 0 degree Celsius= 273K
333.0 degrees Celsius= 606K
Set up: (1.00L)/ (273K)= V2/ (606.0K)
⇒ V2= (1.00L)/ (273K)* (606.0K)= 2.22L
Hope this would help :))
First, we are discussing reversible reactions here, since the reaction is proceeded in both directions forming both reactants and products.
The reaction is symbolized as:
A + B <.........> C + D
The first given is:
The rate of appearance of D is twice the disappearance of A
This means that the coefficient of D in the reaction is twice the coefficient of A
The second given is:
The rate of appearance of D is one third the disappearance of B.
This means that the coefficient of D in the reaction is 1/3 that of B. This also means that the coefficient of B is 3 times that of D.
Combining these two pieces of information, we will find that the best equation that resembles this scenario is:
<span>A + 6 B <.........> C + 2 D </span>
Answer : The unit of
in mol/L.mm Hg is, 
Explanation :
As we know that the
is the Henry's Law constant for argon at
is, 
Now we have to determine the unit of
in mol/L.mm Hg
Conversion used for pressure from atm to mmHg is:
1 atm = 760 mmHg
So,


Thus, the unit of
in mol/L.mm Hg is, 