Answer:
The new current in the straight wire is 4.98 A
Explanation:
Given;
initial magnetic force on the wire, F₁ = 0.017 N
initial current flowing on the straight wire, I₁ = 1.1 A
When the current in the wire is changed,
new magnetic force on the wire, F₂ = 0.077 N
the new current in the wire, I₂ = ?
Applying equation of magnetic force on conductor;
F₁ = I₁BLsinθ
F₂ = I₂BLsinθ
BLsinθ = F₁/I₁ = F₂/I₂
I₂ = (F₂I₁)/F₁
I₂ = (0.077 x 1.1) / 0.017
I₂ = 4.98 A
Therefore, the new current in the straight wire is 4.98 A
