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3 years ago

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A straight wire in a magnetic field experiences a force of 0.017 N when the current in the wire is 1.1 A. The current in the wir

e is changed, and the wire experiences a force of 0.077 N as a result. What is the new current

1 answer:

mel-nik [20]3 years ago

3 0

Answer:

The new current in the straight wire is 4.98 A

Explanation:

Given;

initial magnetic force on the wire, F₁ = 0.017 N

initial current flowing on the straight wire, I₁ = 1.1 A

When the current in the wire is changed,

new magnetic force on the wire, F₂ = 0.077 N

the new current in the wire, I₂ = ?

Applying equation of magnetic force on conductor;

F₁ = I₁BLsinθ

F₂ = I₂BLsinθ

BLsinθ = F₁/I₁ = F₂/I₂

I₂ = (F₂I₁)/F₁

I₂ = (0.077 x 1.1) / 0.017

I₂ = 4.98 A

Therefore, the new current in the straight wire is 4.98 A

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Answer:

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Explanation:

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k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

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$n=\dfrac{mN_AZe}{M}$

$q=imbalance\times \dfrac{mN_AZe}{M}$

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$q_2=0.0004\times \dfrac{48\times 6.022\times 10^{23}\times 18\times 1.6\times 10^{-19}}{0.018}\\\Rightarrow q_1=1849958.4\ C$

Electrical force is given by

$F=\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=\dfrac{8.99\times 10^{9}\times 3699916.8\times 1849958.4}{30^2}\\\Rightarrow F=6.8370869499\times 10^{20}\ N$

The electrostatic force of attraction between them is $6.8370869499\times 10^{20}\ N$

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Answer: Different fuel components boil at different temperatures, allowing them to be separated.

Explanation:

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Answer:

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As we know that the formula of center of gravity is given as

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harkovskaia [24]

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200 N x 10 m = 2000 Nm

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