The heat of reaction : 50.6 kJ
<h3>Further explanation</h3>
Based on the principle of Hess's Law, the change in enthalpy of a reaction will be the same even though it is through several stages or ways
Reaction
N₂(g) + 2H₂(g) ⇒N₂H₄(l)
thermochemical data:
1. N₂H₄(l)+O₂(g)⇒N₂(g)+2H₂O(l) ΔH=-622.2 kJ
2. H₂(g)+1/2O₂(g)⇒H₂O(l) ΔH=-285.8 kJ
We arrange the position of the elements / compounds so that they correspond to the main reaction, and the enthalpy sign will also change
1. N₂(g)+H₂O(l) ⇒ N₂H₄(l)+O₂(g) ΔH=+622.2 kJ
2. H₂(g)+1/2O₂(g)⇒H₂O(l) ΔH=-285.8 kJ x 2 ⇒
2H₂(g)+O₂(g)⇒2H₂O(l) ΔH=-571.6 kJ
Add reaction 1 and reaction 2, and remove the same compound from different sides
1. N₂(g)+2H₂O(l) ⇒ N₂H₄(l)+O₂(g) ΔH=+622.2 kJ
2.2H₂(g)+O₂(g)⇒2H₂O(l) ΔH=-571.6 kJ
-------------------------------------------------------------------- +
N₂(g) + 2H₂(g) ⇒N₂H₄(l) ΔH=50.6 kJ
Answer: Adiabatic process is a process in which <u>heat</u> is constant
Explanation:
The processes in which temperature remains constant is called isothermal process.
The process in which Volume remains constant is called isochoric process.
The process in which pressure remains constant is called isobaric process.
The process in which no heat is gained or lost by the system, Hence heat remains constant is called as adiabatic process.
Thus option d) heat is correct
Answer:
and birds can fly without wings es hora de vomer
The type of covalent bond is formed between amino acid molecules during protein synthesis will be <u>"peptide bond".</u>
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A peptide bond would be a sort of covalent link that connects an amino acid's carboxyl group to its amino group. Amino acids itself were comprised of atoms bonded together through covalent bonds.
Two atoms share an electron pair equally in a covalent link. Peptide (amide) but also disulfide links between amino acids, as well as C-C, C-O, and C-N bonds within amino acids, represent examples of significant covalent bonds.
Therefore, the type of covalent bond is formed between amino acid molecules during protein synthesis will be <u>"</u><u>peptide bond"</u><u>.</u>
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To know more about covalent bond
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