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Helga [31]
3 years ago
7

At equilibrium, Keq for the following reaction is equal to 3.5: SO2 + NO20 È SO3 + NO a) Is a beaker containing 2.5 M SO2, 2.0 M

NO,, 1.1 M SO3, and 6.0 M NO, at equilibrium? b) If the reaction is not in equilibrium, in which direction must the reaction to proceed to reach equilibrium?​
Chemistry
1 answer:
liraira [26]3 years ago
4 0
Keq=[SO3][SO2] /[SO2][NO2]
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If an automobile air bag has a volume of 11.5 l , what mass of nan3 (in
True [87]
Moles of NaN3 at STP  = volume of gas / 22.4 = 11.5/22.4 = 0.5mole. Massof NaN3 = moles of NaN3 x molecular weight = 0.5 x 65 = 32.5 grams.
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3 years ago
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Acetaminophen is the generic name of the pain reliever in Tylenol and some other headache remedies- The compoundhas the molecula
slega [8]

<u>Answer:</u> The mass percentage of carbon element is 63.57 %, hydrogen element is 5.96 %, nitrogen element is 9.28 % and oxygen element is 21.19 %

<u>Explanation:</u>

We are given:

A chemical compound having chemical formula of C_8H_9NO_2. This compound is made by the combination of carbon, hydrogen, nitrogen and oxygen elements.

1 mole of acetaminophen contains 8 moles of carbon atom, 9 moles of hydrogen atom, 1 mole of nitrogen atom and 2 moles of oxygen atom

Mass of carbon element = (8\times 12)=96g/mol

Mass of hydrogen element = (9\times 1)=9g/mol

Mass of nitrogen element = (1\times 14)=14g/mol

Mass of oxygen element = (2\times 16)=32g/mol

Mass of the compound = 151 g/mol

To calculate the percentage composition of an element in a compound, we use the equation:

\%\text{ composition of an element}=\frac{\text{Mass of element}}{\text{Mass of compound}}\times 100      ........(1)

  • <u>For carbon element:</u>

Putting values in equation 1, we get:

\% \text{ composition of carbon element}=\frac{96}{151}\times 100\\\\\% \text{ composition of carbon element}=63.57\%

  • <u>For hydrogen element:</u>

Putting values in equation 1, we get:

\% \text{ composition of hydrogen element}=\frac{9}{151}\times 100\\\\\% \text{ composition of hydrogen element}=5.96\%

  • <u>For nitrogen element:</u>

Putting values in equation 1, we get:

\% \text{ composition of nitrogen element}=\frac{14}{151}\times 100\\\\\% \text{ composition of nitrogen element}=9.28\%

  • <u>For oxygen element:</u>

Putting values in equation 1, we get:

\% \text{ composition of oxygen element}=\frac{32}{151}\times 100\\\\\% \text{ composition of oxygen element}=21.19\%

Hence, the mass percentage of carbon element is 63.57 %, hydrogen element is 5.96 %, nitrogen element is 9.28 % and oxygen element is 21.19 %

6 0
3 years ago
HELP ME!! THANH YOU If an atom has 80 protons and 121 neutrons, and is not in an excited state, how many electrons would Bohr sa
wariber [46]
I think it might be 80
5 0
3 years ago
With the Haber process, how many grams of hydrogen will be needed to make 0.3820 pounds of ammonia? Needed to 3 decimal places f
masya89 [10]

30.576 g of hydrogen

Explanation:

First we need to covert the pound in grams.

if        1 pound is equal to 453.592 grams

then  0.3820 pounds is equal to X grams

X = (0.3820 ×  453.592) / 1 = 173.272 grams

So we have 173.272 grams of ammonia.

Now we look at the chemical reaction where hydrogen (H₂) reacts with nitrogen (N₂) to produce ammonia (NH₃):

3 H₂ + N₂ → 2 NH₃

number of moles = mass / molar weight

number of moles of ammonia = 173.272 / 17 = 10.192 moles

Now taking in account the chemical reaction, we formulate the following reasoning:

if         3 moles of hydrogen produce 2 moles of ammonia

then    Y moles of hydrogen produce 10.192 moles of ammonia

Y = (3 × 10.192) / 2 = 15.288 moles of hydrogen

mass = number of moles × molar weight

mass of hydrogen = 15.288 × 2 = 30.576 g

Learn more about:

problems with number of moles

brainly.com/question/13950919

brainly.com/question/13947602

#learnwithBrainly

4 0
4 years ago
What is the formula for finding the density of<br> an object?
TEA [102]
The answer would be:
D = M/V

D=Density
M= mass
V= volume
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3 years ago
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