My answer to the problem is as follows:
<span>1. Use the kinematic formula
Vf = Vi + a*t
for a, Vi = 3.0 m/s, a = 0.5 m/s/s, and t = 7.o s.
for b, Vf = 0, Vi = 3.0 m/s, and a = -0.60 m/s/s.
I hope my answer has come to your help. God bless and have a nice day ahead!
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Answer:
Explanation:
ASSUMING that block = sled AND that the rope is parallel to the slope.
The force acting parallel due to the weight is
13.6(9.81)sin35.5 = 77.475 N
The maximum friction force is
(0.45)13.6(9.81)cos35.5 = 48.877 N
If rope tension is T
77.475 - 48.877 < T < 77.475 + 48.877
28.6 N < T < 126 N
28.6 N will occur if the block is on the verge of sliding downhill
126 N will occur if the block is on the verge of sliding uphill
Could be any value between them.
Kinetic energy is the energy possessed by a body in motion while potential energy is the energy of a body at rest.
Kinetic energy is given by E=1/2MV² where M is the mass of the body while V is the velocity of the body.
To get mass we can use the formula M= 2 Ek/V² (Making M the subject)
hence mass = (2 ×675)÷35²
= 1.102 kg
Answer:
2 ans : the bell has 8550 J energy
Answer:
Average acceleration is 
Explanation:
It is given that,
Initial velocity, u = 0
Final velocity, v = 6.5 km/s = 6500 m/s
Time taken, t = 60 s
Acceleration, 

Since, 
So, 
So, the angular acceleration of the missile is
. Hence, this is the required solution.