Answer:
–36 KJ.
Explanation:
The equation for the reaction is given below:
2B + C —› D + E. ΔH = – 24 KJ
From the equation above,
1 mole of D required – 24 KJ of energy.
Now, we shall determine the energy change associated with 1.5 moles of D.
This can be obtained as illustrated below:
From the equation above,
1 mole of D required – 24 KJ of energy
Therefore,
1.5 moles of D will require = 1.5 × – 24 = –36 KJ.
Therefore, –36 KJ of energy is associated with 1.5 moles of D.
Answer:
The maximum mass of carbon dioxide that could be produced by the chemical reaction is 70.6gCO_{2}
Explanation:
1. Write down the balanced chemical reaction:

2. Find the limiting reagent:
- First calculate the number of moles of hexane and oxygen with the mass given by the problem.
For the hexane:

For the oxygen:

- Then divide the number of moles between the stoichiometric coefficient:
For the hexane:

For the oxygen:

- As the fraction for the oxygen is the smallest, the oxygen is the limiting reagent.
3. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction:
The calculations must be done with the limiting reagent, that is the oxygen.

Answer:
285.4 moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 atm.
Explanation:
An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P * V = n * R * T
In this case:
- P= 200.8 atm
- V= 35 L
- n=?
- R= 0.082

- T= 27.3 C= 300.3 K (being O C= 273 K)
Replacing:
200.8 atm* 35 L= n* 0.082
* 300.3 K
Solving:

n= 285.4 moles
<u><em>285.4 moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 atm.</em></u>
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