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iris [78.8K]
3 years ago
11

Suppose you spray your sister with water from a garden hose. The water is supplied to the hose at a rate of 0.625×10−3 m3/s and

the diameter of the nozzle you hold is 5.19×10−3 m. At what speed v does the water exit the nozzle?
Physics
1 answer:
Tems11 [23]3 years ago
4 0

Answer:

<em>0.153 m/s</em>

<em></em>

Explanation:

The flowrate Q = 0.625 x 10-3 m^3-/s

The diameter of the nozzle d = 5.19 x 10^-3 m

the velocity V = ?

The cross-sectional area of the flow A = \pi d^{2}/4

==> (3.142 x 5.19 x 10^-3)/4 = 4.077 x 10^-3 m^2

From the continuity equation,

Q = AV

V = Q/A = (0.625 x 10-3)/(4.077 x 10^-3) = <em>0.153 m/s</em>

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