Consider a circular cylinder in hypersonic flow, with its axis perpendicular to the flow. Let φ be the angle measured between ra
dii drawn to the leading edge (the stagnation point) and to any arbitrary point on the cylinder. The pressure coefficient distribution along the cylindrical surfaces is given by Cp = 2cos 2φ for 0 ≤ φ ≤ π/2 and 3π/2 ≤ φ ≤ 2π and Cp = 0 for π/2 ≤ φ ≤ 3π/2.
Calculate the drag coefficient for the cylinder, based on the projected frontal area of the cylinder.
Calculate the drag coefficient for the cylinder, based on the projected frontal area of the cylinder.
1 answer:
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Answer:
Therefore, the horizontal displacement of end F of rod EF is 0.4797 mm
Explanation:
solution is mentioned in steps.
Answer:
F=989.6 N
Explanation:
Given that
Diameter of shaft = 70 mm
Diameter of bearing sleeve =70.2 mm
So clearance h=0.1 mm
Speed V= 400 mm/s
Length of shaft = 250 mm
We know that
μ= 900 x 0.005 Pa-s
μ= 4.5 Pa-s
As we know that
From Newton's law of viscosity ,the shear stress given as follows
We also know that
Force = shear stress x area
Now by putting the values
So force
F= 18,000 x π x 0.07 x 0.25
F=988.6 N