Answer:
 14.506°C
Explanation:
Given data :
flow rate of water been cooled = 0.011 m^3/s 
inlet temp = 30°C + 273 = 303 k 
cooling medium temperature = 6°C  + 273 = 279 k
flow rate of cooling medium = 0.02 m^3/s 
Determine the outlet temperature 
we can determine the outlet temperature by applying the relation below
Heat gained by cooling medium = Heat lost by water 
= ( Mcp ( To - 6 )  =  Mcp ( 30 - To ) 
since the properties of water and the cooling medium ( water ) is the same 
= 0.02 ( To - 6 ) = 0.011 ( 30 - To ) 
= 1.82 ( To - 6 ) = 30 - To
hence To ( outlet temperature ) = 14.506°C
 
        
             
        
        
        
Seriously? Ok 
first, get some good quality metal, preferably aluminum, if you want to avoid rust.
build in the the shape of a robot, you can use a doll to help you if you are a beginner, but feel free to shape it the a Star Wars Character! 
create an AI (now you said robot not AI) and fix everything up.
        
             
        
        
        
Answer:Decay rate constant,k  = 0.00376/hr 
 Explanation:
 IsT Order  Rate of reaction is given as 
 In At/ Ao = -Kt
where [A]t is the final concentration at time  t  and  [A]o  is the inital concentration at time 0, and  k  is the first-order rate constant.
Initial concentration = 80 mg/L
Final concentration = 50 mg/L
Velocity = 40 m/hr
Distance= 5000 m
Time taken = Distance / Time
               5000m / 40m/hr = 125 hr
In At/ Ao = -Kt
In 50/80 = -Kt
-0.47 = -kt
- K= -0.47 / 125
 k = 0.00376 
Decay rate constant,k  = 0.00376/hr 
 
        
             
        
        
        
Answer:
Timing Diagrams 15 pts. A 10 MHz clock that generates a 0 to 5V pulse train with a 30% duty cycle is connected to input X of a two input OR gate that has a 20nS propagation delay. The clock also goes to an inverter with a 10 ns propagation delay. The output of the inverter goes to the Y input of the OR gate. a) Draw the circuit. 2 pts. b) Plot the output of the clock for two cycles. Show times and voltages. 5 pts. c) On the same page as part (b) plot the output of the inverter. Show times and voltages. 3 pts. d) On the same page as parts (b & c) plot the output of the OR gate. Show times and voltages. 5 pts.
 
        
             
        
        
        
Answer:
#include <iostream>
#include <iomanip>
using namespace std;
class pointType
{
public:
pointType()
{
x=0;
y=0;
}
pointType::pointType(double x,double y)
{
this->x = x;
this->y = y;
}          
void pointType::setPoint(double x,double y)
{
this->x=x;
this->y=y;
}
void pointType::print()
{
cout<<"("<<x<<","<<y<<")\n";
}
double pointType::getX()
{return x;
}
double pointType::getY()
{return y;
}
private:
    double x,y;
};
int main()
{
pointType p2;
double x,y;
cout<<"Enter an x Coordinate for point ";
cin>>x;
cout<<"Enter an y Coordinate for point ";
cin>>y;
p2.setPoint(x,y);
p2.print();
system("pause");    
return 0;
}