Empirical formula of ionic compound is FeO. In which the composition of atoms is 1 : 1.
Empirical formula of an ionic compound is defined as the formula which gives whole number ratio of atoms of various elements present in molecule of compund.
mass of iron in compound = 34.95 g
molar mass of iron = 55.8 g
mass of oxygen in compound = 15.05 g
molar mass of oxygen = 32 g
number of moles of iron present in the compound are ratio of mass of iron in compound/ molar mass of iron
number of moles of iron in compound= 34.95 / 55.8 = 0.6263 ~ 1
number of moles oxygen in compound= 15.05/ 32 = 0.473 ~ 0.5
the ratio of the number of oxygen atoms to number of iron atoms present in one formula unit of iron compund is 2×0.5 / 1 = 1 : 1
Hence , the required empirical formula of iron compound is FeO.
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Answer: im pretty sure it's electrical.
If u seperate them into halves at a time
Answer :
The balanced chemical reaction is,
From this balanced chemical reaction, we conclude that
2 moles of iron oxide react with the 3 moles of carbon to give 4 moles of iron and 3 moles of carbon dioxide.
Therefore, the valid mole ratio from the balanced chemical reaction is,
Answer:
For any cross between Homozygous dominant and Homozygous recessive individual the offspring will always be 100% Heterozygous dominant, that is all will have Rr.
Explanation: