When ammonia is reacted with HCl it abstracts proton from acid and forms Ammonium Ion and Chloride Ion.
NH₃ + HCl → ⁺NH₄ + Cl⁻ (simply Written NH₄Cl)
Structure,
The structure of Ammonium Chloride is among those structures which contains all three types of bonding's, i.e.
Ionic Bond
Covalent Bond
Coordinate Covalent Bond
Three Hydrogen atoms previously bonded with Nitrogen are covalent in nature. The new incoming proton from HCl forms co-ordinate covalent bond with Nitrogen and Chloride Ion containing negative charge make Ionic Bond with the positive Ammonium Ion. In question, if the line between Nitrogen and Chlorine atom is assumed covalent then it is incorrect. Structure is shown below,
The pure substance of water mixes with the waste. The waste does not dissolve into the water, therefore it is a mixture.
Answer:
The answer is in the explanation
Explanation:
Single displacement reactions: In these reactions, a more reactive element kicks out a less reactive element from a compound.
Ex. Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)
In this example, Zn is more reactive than H, then Zn displaces H from the compound.
Double displacement reactions: In these kind of reactions 2 elements are displaced from the different compounds, these elements interchange positions.
Ex. CuCl2(aq) + 2 AgNO3(aq) → Cu(NO3)2(aq) + 2 AgCl(s)
In the example, Cu displaces Ag and Ag displaces Cu, they interchange positions.
Answer:
ΔH°f P4O10(s) = - 3115.795 KJ/mol
Explanation:
- P4O10(s) + 6H2O(l) ↔ 4H3PO4(aq)
- ΔH°rxn = ∑νiΔH°fi
∴ ΔH°rxn = - 327.2 KJ
∴ ΔH°f H2O(l) = - 285.84 KJ/mol
∴ ΔH°F H3PO4(aq) = - 1289.5088 KJ/mol
⇒ ΔH°rxn = (4)(- 1289.5088) - (6)(- 285.84) - ΔH°f P4O10(s) = - 327.2 KJ
⇒ ΔH°f P4O10(s) = - 5158.035 + 1715.04 + 327.2
⇒ ΔH°f P4O10(s) = - 3115.795 KJ/mol
Metal because it’s more stronger