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3 years ago

In a compoumd are atoms physically or chemically combined

Physics

1 answer:

Andrei [34K]3 years ago

3 0

Answer:

They are...if I'm correct Chemically combined, sorry if I'm wrong.

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On a summer afternoon, the sand on the beach can get very hot. When you step on the sand in bare feet, you can burn yourself.

8_murik_8 [283]

<span>Heat from the Sun is transferred to the sand without direct contact. This heat is then transferred to your feet by direct contact.</span>

8 0

3 years ago

Read 2 more answers

While at a construction site, you see a crane lift a 1000kg steel beam up to a height of 10m in a time period of 5.0 seconds. A

storchak [24]

Answer:

Car has more power output than crane

Explanation:

We have given that mass of the crane m = 1000 kg

Height through which crane lift the steel beam h = 10 m

Acceleration due to gravity $g=9.8m/sec^2$

So work done by crane $W=mgh=1000\times 9.8\times 10=98000j$

Time period is given as t = 5 sec

We know that power $P=\frac{W}{t}=\frac{98000}{5}=19600watt$

Now mass of the car = 1000 kg

Initial velocity u = 0 m /sec

Final velocity v = 10 m/sec

We know that work done is equal to the change in kinetic energy

So work done $=\frac{1}{2}mv^2-\frac{1}{2}mu^2$

$=\frac{1}{2}\times 1000\times 10^2-\frac{1}{2}\times 1000\times 0^2=50000j$

Time ids given as t = 2 sec

So power $P=\frac{W}{t}=\frac{50000}{2}=25000watt$

So car has more power output than crane

8 0

3 years ago

I need help on this!

sergij07 [2.7K]

Try looking it up. that might help

8 0

3 years ago

Two 2.0cm×2.0cm metal electrodes are spaced 1.0 mm apart and connected by wires to the terminals of a 9.0 v battery. What is the

Fantom [35]

Answer:

The charge on each electrode is

$q=0.354 x10^{-12}$

Explanation:

The charge to find the equation is development

V=9v

$d=1.0 mm\\A=2cm*2cm=0.02m*0.02m\\A=4x10^{-4} \\E_{o} =8.85x10^{-12} (\frac{C^{2} }{N*m^{2} } )$

$q=C*V$

$C=\frac{E_{o}*A }{d} \\C=\frac{8.85x10^{-12} *4x10^{-4} }{0.01}=0.354 \\$

$q=0.354*9v\\q=3.186x10^{-12} C$

3 0

3 years ago

A dog of mass 10 kg sits on a skateboard of mass 2 kg that is initially traveling south at 2 m/s. The dog jumps off with a veloc

Tasya [4]

Answer:

17 m/s south

Explanation:

$m_1$ = Mass of dog = 10 kg

$m_2$ = Mass of skateboard = 2 kg

v = Combined velocity = 2 m/s

$u_1$ = Velocity of dog = 1 m/s

$u_2$ = Velocity of skateboard

In this system the linear momentum is conserved

$(m_1+m_2)v+m_1u_1+m_2u_2=0\\\Rightarrow u_2=-\dfrac{(m_1+m_2)v+m_1u_1}{m_2}\\\Rightarrow u_2=-\dfrac{(10+2)2+10\times 1}{2}\\\Rightarrow u_2=-17\ m/s$

The velocity of the skateboard will be 17 m/s south as the north is taken as positive

3 0

3 years ago