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olga nikolaevna [1]
3 years ago
7

An instructor gives a demonstration in which he makes a standing wave on a long thin slinky. The slinky is 6.0 meters long. If y

ou see 3 loops on the slinky when the instructor shakes the end of the slinky at a rate of 2.50 cycles per second, then the speed (in m/s) of transverse traveling waves on the slinky is
Physics
1 answer:
Naily [24]3 years ago
8 0

The characteristics of standing waves allows to find the result for the speed of the wave is:

  • The speed wave is:  v = 10 m / s

The wave is a way of transmitting energy without mass displacement, , in the attachment we can see a diagram of the standing wave.

Each cycle corresponds to half a wavelength,  they indicate that the frequency is 2.50 Hz and there are three cycles, so the wavelength is:

      L = n \frac{\lambda}{2}

      λ = 2L/n

      λ = 2 6 /3

       λ = 4 m

Wave speed is related to wavelength and frequency

        v = λ f

         v = 4 2.5

         v = 10 m / s

In conclusion, using the characteristics of standing waves we can find the result for the speed of the wave is:

  • The wave speed is:   v = 10 m / s

Learn more here: brainly.com/question/12536719

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<span>In that particular situation, you can prove it like this: </span>

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<span>launch angle is α </span>

<span>initial vertical velocity is </span>
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<span>horizontal velocity is </span>
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<span>total time in the air is the the time it needs to fall back to a height of 0 m, so </span>
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<span>d = distance = 0 m </span>
<span>v = initial vertical velocity = Vv = Vo×sin(α) </span>
<span>t = time = ? </span>
<span>a = acceleration by gravity = g (= -9.8 m/s²) </span>
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<span>0 = Vo×sin(α)×t + g×t²/2 </span>
<span>0 = (Vo×sin(α) + g×t/2)×t </span>
<span>t = 0 (obviously, the projectile is at height 0 m at time = 0s) </span>
<span>or </span>
<span>Vo×sin(α) + g×t/2 = 0 </span>
<span>t = -2×Vo×sin(α)/g </span>

<span>Now look at the horizontal range. </span>
<span>r = v × t </span>
<span>where </span>
<span>r = horizontal range = ? </span>
<span>v = horizontal velocity = Vh = Vo×cos(α) </span>
<span>t = time = -2×Vo×sin(α)/g </span>
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<span>r = -(Vo)²×sin(2α)/g </span>

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<span>dr/dα = -2 × (Vo)² × cos(2α) / g </span>

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<span>cos(2α) = 0 </span>
<span>2α = 90° </span>
<span>α = 45° </span>
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