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2 years ago

A neutral aluminum atom is ionized and loses 3 electrons. What is the

Chemistry

1 answer:

Nata [24]2 years ago

6 0

Explanation:

The neutral aluminium atom loses all 3 of its valence electrons to obtain a stable octet structure.

The aluminium ion has a positive charge of 3.

=> Al3+, Charge = +3.

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If you react 156.0 g of calcium chloride with an excess NaOH, how much sodium chloride should you get?

laiz [17]

Answer:

164.3g of NaCl

Explanation:

Based on the chemical equation:

CaCl2 + 2NaOH → 2NaCl + Ca(OH)2

where 1 mole of CaCl2 reacts with 2 moles of NaOH

To solve this question we must convert the mass of CaCl2 to moles. Using the chemical equation we can find the moles of NaCl and its mass:

Moles CaCl2 -Molar mass: 110.98g/mol-

156.0g CaCl₂ * (1mol / 110.98g) = 1.4057 moles CaCl2

Moles NaCl:

1.4057 moles CaCl2 * (2mol NaCl / 1mol CaCl2) = 2.811 moles NaCl

Mass NaCl -Molar mass: 58.44g/mol-

2.811 moles NaCl * (58.44g / mol) = 164.3g of NaCl

7 0

2 years ago

In Keynes's liquidity preference framework, as the expected return on bonds increases (holding everything else unchanged), the e

Julli [10]

Answer:

the correct words to fill up the blank spaces are falls and money

Explanation:

.1. the expected return on money falls

.2. causing the demand for money to fall.

3 0

2 years ago

What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)

nikdorinn [45]

Answer : The volume of $O_2$ consumed are, $0.75\times 2\times 22.4$ L.

Explanation :

The balanced chemical reaction will be:

$4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)$

First we have to calculate the moles of Al.

$\text{Moles of }Al=\frac{\text{Mass of }Al}{\text{Molar mass of }Al}$

Molar mass of Al = 27 g/mole

$\text{Moles of }Al=\frac{55g}{27g/mol}=2mole$

Now we have to calculate the moles of $O_2$ .

From the reaction we conclude that,

As, 4 mole of Al react with 3 moles of $O_2$

So, 2 mole of Al react with $\frac{3}{4}\times 2=0.75\times 2$ moles of $O_2$

Now we have to calculate the volume of $O_2$ consumed.

As we know that, 1 mole of substance occupies 22.4 liter volume of gas.

As, 1 mole of $O_2$ occupies 22.4 liter volume of $O_2$ gas

So, $0.75\times 2$ mole of $O_2$ occupies $0.75\times 2\times 22.4$ liter volume of $O_2$ gas

Therefore, the volume of $O_2$ consumed are, $0.75\times 2\times 22.4$ L.

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2 years ago

How did rutherford know that the nucleus was positively charged?

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