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svet-max [94.6K]
1 year ago
14

Which quantity must be determined experimentally in order to determine the bonding atomic radius of an atom?.

Chemistry
1 answer:
spin [16.1K]1 year ago
7 0

Only by measuring the separation between the nuclei of two contacting atoms and halving that distance can one determine the radius of an atom. The illustrations show how the environment around an atom can cause it to have a varied radius, even if it is the same atom.

<h3>How can the atomic size of an element be determined?</h3>

By measuring the distance between the two atoms after two are united, we may determine the atomic size of the new molecule. The third technique for determining an element's atomic size is to create a single covalent link between two atoms and measure the space between them.

Atomic radii in the periodic table change from left to right across a row and from top to bottom along a column. Because of these two patterns, the periodic table's bottom left corner contains the biggest atoms, while the upper right corner has the smallest.

Learn more about radius of an atom refer

brainly.com/question/13126562

#SPJ1

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In the question, we are told that there are;

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We also know that he is making a sandwich that has 2 pieces of both cheese and bread.

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Each loaf should have two pieces of each bread and the cheeses make a total of four pieces.

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4 0
2 years ago
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3 years ago
What is true at stp? A)the temperature is 273.15 kelvin, B)one mole of gas occupies one liter of volume. C)pressure is at 101 vo
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3 years ago
Aluminum and oxygen react according to the following equation: 4Al + 3O2 -&gt; 2Al2O3 In a certain experiment, 4.6g Al was react
stiv31 [10]

Answer:

Percent yield: 78.2%

Explanation:

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<em>4 moles of Al produce 2 moles of Al₂O₃</em>

<em />

To find percent yield we need to find theoretical yield (Assuming a yield of 100%) and using:

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Moles of 4.6g of Al (Molar mass: 26.98g/mol) are:

4.6g Al × (1mol / 26.98g) = 0.1705 moles of Al.

As 4 moles of Al produce 2 moles of Al₂O₃, theoretical moles of Al₂O₃ obtained from 0.1705 moles of Al are:

0.17505 moles Al × (2 moles Al₂O₃ / 4 moles Al) = <em>0.0852 moles of Al₂O₃</em>,

In grams (Molar mass Al₂O₃ = 101.96g/mol):

0.0852 moles of Al₂O₃ × (101.96g / mol) =

<h3>8.7g of Al₂O₃ can be produced (Theoretical yield)</h3>

Thus, Percent yield is:

(6.8g / 8.7g) × 100 =

<h3>78.2% </h3>
8 0
3 years ago
The gas in a cylinder has a volume of 8 liters at a pressure of 101 kPa. The pressure of the gas is increased to 206 kPa. Assumi
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