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3 years ago

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A 100kg object initially traveling at 20 m/s is decelerated to 10 m/s during a time interval of 10 seconds. What is the final mo

mentum of the object?

2 answers:

ruslelena [56]3 years ago

7 0

Answer: 1000 Ns

Explanation: I might have answered a lil late, I'm pretty sure this is for physics right?

Stels [109]3 years ago

4 0

Answer:

pointsjdisjdbziskdnxusndnbzbzksod

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The force that generates wind is ________. centrifugal force pressure gradient force coriolis force gravity force

Veseljchak [2.6K]

~Hello There! ^_^

Your question: The force that generates wind is ___________.

Your answer: The force that generates wind is pressure gradient force.

The answer to fill up the blank is pressure gradient force.

Hope this helps!

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3 years ago

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Melvin is traveling south on I-95 at 29 m/s (65 mph) when a deer jumps into his path, 50 m ahead. a. If his reaction time is 0.1

aleksandr82 [10.1K]

Answer:

a. 5.22 meters

b. 2.9 seconds

c. No, Melvin does not hit the deer

Explanation:

The parameters with which Melvin is travelling are as follows;

The speed of Melvin's motion, u = 29 m/s

The distance from Melvin at which the deer jumps into the path = 50 m

a. Distance, d = Velocity, u × Time, t

The time it takes Melvin to react = 0.18 seconds

The distance, "d₁" Melvin travels before his foot hits the break = The velocity with which Melvin was traveling, "u" × The time duration it takes Melvin to hit the brakes, "t₁"

∴ d₁ = 29 m/s × 0.18 s = 5.22 m

The distance, Melvin travels before his foot hits the break = d₁ = 5.22 m

b. Melvin's acceleration after his foot hits the brakes, a = -10 m/s²

Therefore, we have;

The time it takes "t₂" it takes for him to come to a complete stop given as follows;

y = u + a × t₂

Where;

v = The final velocity after Melvin comes to a complete stop = 0 m/s

By substituting the known values, we have;

0 = 29 m/s + (-10 m/s²) × t₂ = 29 m/s - 10 m/s² × t₂

∴ 29 m/s = 10 m/s² × t₂

t₂ = (29 m/s)/(10 m/s²) = 2.9 s

The time it takes it takes for him to come to a complete stop = t₂ = 2.9 s

c. The distance, "d₂", Melvin reaches while accelerating (decelerating) at -10 m/s² to come to a complete stop is given as follows;

v² = u² + 2·a·d₂

Therefore, we have;

0² = (29 m/s)² + 2 × (-10 m/s) × d₂ = (29 m/s)² - 2 × 10 m/s × d₂

∴ (29 m/s)² = 2 × 10 m/s × d₂

d₂ = ((29 m/s)²)/(2 × 10 m/s²) = (841 m²/s²)/(20 m/s²) = 42.05 m

The distance, Melvin reaches while accelerating (decelerating) at -10 m/s² to come to a complete stop = d₂ = 42.05 m

Given that d₂ = 42.05 m < 50 m (The distance separating Melvin's initial location and the deer, Melvin does not hit the deer.

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3 years ago

A snowboarder is sliding back and forth on a half pipe at one point she leaves the top of the half pipe and slides to the other

r-ruslan [8.4K]

Answer:

he kinetic energy increases on the descent, being maximum at the lowest point of the trajectory.

Explanation:

In these semicircular sections the skaters slide from one side to the other, in the downward path their kinetic energy increases and their potential energy decreases; When it leaves the ramp and is in the air, the kinetic energy decreases rapidly, up to the point of maximum height where the kinetic energy is zero.

Consequently, the kinetic energy increases on the descent, being maximum at the lowest point of the trajectory.

3 0

3 years ago

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Mia wanted to know how Earth’s movements created new landforms. She decided to read about folded mountains and their characteris

kifflom [539]

Answer:

I’m pretty sure it’s D

Explanation:

the crust breaks and shifts when that happens

hope dis helps ^-^

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3 years ago

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a certain hydraulic jack is used for lifting load. a force of 250N is applied on a small piston with a diameter of 80cm while th

anzhelika [568]

The maximum mass of a load that can be lifted by the jack and the distance covered are:

m = 160.2 Kg

h = 25 cm

Given that a certain hydraulic jack is used for lifting load. a force of 250N is applied on a small piston with a diameter of 80cm while the diameter of the larger piston is 2.0m.

The parameters given are

$F_{1}$ = 250

$A_{1}$ = Area of the small piston = π $r^{2}$

$A_{1}$ = 22/7 x $0.4^{2}$

$A_{1}$ = 0.5 $m^{2}$

$F_{2}$ = ?

$A_{2}$ = Area of the large piston = π $r^{2}$

$A_{2}$ = π x 1

$A_{2}$ = 3.14 $m^{2}$

To calculate the force on the large piston, we will use the below formula

$F_{1}$ / $A_{1}$ = $F_{2}$ / $A_{2}$

Substitute all the parameters into the equation

250/0.5 = $F_{2}$ /3.14

$F_{2}$ = 1570 N

To calculate the maximum mass of a load that can be lifted by the jack, let us apply Newton second law

F = mg

1570 = 9.8m

m = 1570/9.8

m = 160.2 Kg

.(take g=9.81ms^-2)

If the applied force moves through a distance of 25cm, the distance through which the load is lifted will be

$F_{1}$ / 0.25 $A_{1}$ = $F_{2}$ / $A_{2}$ h

250/0.125 = 1570/3.14h

make h the subject of the formula

6280h = 1570

h = 1570/6280

h = 0.25 m

Therefore, the distance through which the load is lifted is 25 cm

Learn more here: brainly.com/question/13596980

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3 years ago