A 100kg object initially traveling at 20 m/s is decelerated to 10 m/s during a time interval of 10 seconds. What is the final mo
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Answer:
Given that
speed u=4*10^6 m/s
electric field E=4*10^3 N/c
distance b/w the plates d=2 cm
basing on the concept of the electrostatices
now we find the acceleration b/w the plates to find the horizontal distance traveled by the electron when it hits the plate.
acceleration a=qE/m==
m/s
now we find the horizontal distance traveled by electrons hit the plates
horizontal distance
=
== 3 cm