1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BartSMP [9]
3 years ago
8

A 100kg object initially traveling at 20 m/s is decelerated to 10 m/s during a time interval of 10 seconds. What is the final mo

mentum of the object?
Physics
2 answers:
ruslelena [56]3 years ago
7 0

Answer: 1000 Ns

Explanation: I might have answered a lil late, I'm pretty sure this is for physics right?

Stels [109]3 years ago
4 0

Answer:

pointsjdisjdbziskdnxusndnbzbzksod

You might be interested in
Holding health care personal to lesser standards of care in emergencies is call the what statue?
olga55 [171]

Hello there,

Holding health care personal to lesser standards of care in emergencies is call the what statue?

Answer: A. Good Samaritan


3 0
3 years ago
What is the mass of 2000 ml of an intravenous glucose solution with a density of 1.15 g/ml?
Scorpion4ik [409]

According to the following formula, the answer is 2,300 g or 2.3 kg:

Volume (m)/Mass (m) Equals Density (p) (V)

Here, the density is 1.15 g/mL, allowing the formula described above to result in a mass of 2.00 L:

p=m/V

1.15 g/mL is equal to x g/2.00 L or x g/2,000 mL.

2,000 mL of x g = 1.15 g of g/mL

2.3 kg or 2,300 g for x g.

<h3>How many grams of glucose are in a 1000ml bag of glucose 5?</h3>

Its active ingredient is glucose. This medication includes 50 g of glucose per 1000 ml (equivalent to 55 g glucose monohydrate). 50 mg of glucose is present in 1 ml (equivalent to 55 mg glucose monohydrate). A transparent, nearly colourless solution of glucose in water is what is used in glucose intravenous infusion (BP) at 5% weight-to-volume.

Patients who are dehydrated or who have low blood sugar levels get glucose intravenously. Other medications may be diluted with glucose intravenous infusion before being injected into the body. Other diseases and disorders not covered above may also be treated with it.

learn more about  glucose intravenous infusion refer

brainly.com/question/7057736

#SPJ4

5 0
1 year ago
An old clock has a spring that must be wound to make the clock hands move. Which statement describes the energy of the spring an
kondaur [170]

Answer:

D

Explanation:

When the spring is wound, then it gathers potential energy in the form of tension energy. As it slowly unwinds, the potential energy is converted to kinetic energy of the hands' movements of the clock. This energy is channeled through the use of cogs/gears in the clock.

7 0
3 years ago
Read 2 more answers
Determine the magnitude of the average friction force exerted on the collar when the velocity of the collar at c is 3.39 m/s and
djverab [1.8K]

The magnitude of the average friction force exerted on the collar (F)=  8.641 N

<h3>How can we calculate the magnitude of the average friction force exerted on the collar?</h3>

To calculate the magnitude of the average friction force exerted on the collar we are using the formula,

\frac{1}{2} k(x^2_f - x^2_i ) + F\times y + \frac{1}{2} m v^{2} _{c}  = mgy

Here we are given,

k = The spring has a spring constant.

= 25.5 N/m.

x_f = Final length of the spring .

= \sqrt{1.25^2+1.8^2}  -0.60

= 1.591 m

x_i= The initial length of the spring.

= 1.25−0.60

=0.65 m

y=The collar then travels downward a distance.

=  1.80 m.

m= The mass of the collar.

=3.55 kg

v_c = the velocity of the collar.

= 3.39 m/s.

g = The acceleration due to gravity.

= 9.81 m/s²

We have to calculate the magnitude of the average friction force exerted on the collar = F

Now we put the known values in the above equation, we get;

\frac{1}{2} k(x^2_f - x^2_i ) + F\times y + \frac{1}{2} m v^{2} _{c}  = mgy

Or, \frac{1}{2} \times 25.5 \times((1.591)^2 - (0.65)^2 ) + F\times 1.80 + \frac{1}{2}\times 3.55\times (3.39)^{2}  = 3.55\times 9.81\times 1.80

Or, F= 8.641 N

From the above calculation we can conclude that,

The magnitude of the average friction force exerted on the collar (F)=  8.641 N

Learn more about friction:

brainly.com/question/24338873

#SPJ4

Disclaimer: This question is incomplete in the portal. Here is the complete question.

Question:

The 3.55 kg collar shown below is attached to a spring and released from rest at A. The collar then travels downward a distance of y = 1.80 m. The spring has a spring constant of k = 25.5 N/m. The distance a is given as 1.25 m. The datum for gravitational potential energy is set at the horizontal line through A and B. Determine the magnitude of the average friction force exerted on the collar when the velocity of the collar at c is 3.39 m/s and the spring has an unstretched length of 0.60 m .

6 0
2 years ago
Which federal agency protects ecosystems and supervisors public access the forests
Rainbow [258]

Answer:

United States forest service

3 0
3 years ago
Read 2 more answers
Other questions:
  • Why do scientists look for asteroids that might strike our planet?
    6·2 answers
  • The ocean thermal energy conversion project uses the surface water near tropical islands with a temperature of 20°C as the hot t
    5·1 answer
  • what is the numerical value in meters per second squared of the acceleration of an object experiencing true free fall
    6·1 answer
  • Technician A says that the radiator should always be inspected for leaks and proper flow before installing a rebuilt engine. Tec
    11·1 answer
  • Lithium and francium have similar properties because they
    5·1 answer
  • Can someone please help me with part a and d
    5·2 answers
  • What does transverse wave mean
    9·2 answers
  • Atoms with atomic number ____ or less will not undergo fission.
    9·1 answer
  • Can why hunting and me<br>godinyong the stone Age​
    13·2 answers
  • PLEASE HELP URGENT! this is a homework that is due today but I forgot to do it please help those 2 questions!
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!