Answer:
Explanation:
given that
mass of Ba(NO3)2 = 1.40g
mass of NH2SO3H = 2.50 g
1)to determine the mole of Ba(NO3)2
2) to determine the mass of all three product formed in the reaction
reaction
Ba(NO3)2 + 2NH2SO3H → Ba(NH2SO3)2 + 2HNO3
<u>Solution</u>
we calculate the molar mass of each species by using their atomic masses
BA = 137.33g/mol
N = 14g/mol
O= 16g/mol
H = 1g/mol
S = 32g/mol
calculation
Ba(NO3)2 = Ba + 2N + 6O
= 137.33 + 2X 14 + 6 X 16
= 261.33g/mol
NH2SO3H = N + 3H + S+ 3O
=14 + 3X1 + 32 + 3X 16
= 97g/mol
Ba(NH2SO3)2 = Ba + 2N + 4H +2S +6O
= 137.33 + 2 X 14 + 4 X1 + 2X32 + 6 X 16
= 329.33g/mol
HNO3 = H + n + 3O
= 1 + 14 + 3 X 16
= 63g/mol
Answer:The below file contains the answer
Explanation:
Answer:
Explanation:
https://www.slideshare.net/Thivyaapriya/inorganic-chemistry-group-2
Has all the info you need!
Answer: 50. 4g
Explanation:
First calculate number of moles of aluminium in 38.8g
Moles = 38.8g/ 26.982mol/g
= 1.44mol
By looking at the balance equation you can see that 4 moles of aluminium produce 2 moles of aluminium oxide.
4 = 2
1.4 = x
Find the value of x
x= (1.4×2)/4= 0.72 mol
0.72 moles of aluminium oxide are produced from 38.8g of aluminium
Now find the mass of aluminium produced.
Mass = moles × molar mass
= 0.72mol × 69.93 mol/g
= 50.4g
