Question

B. If the sand you ran across has a specific-heat capacity of 835 J/(kgºc),

Answer 1

Answer: 16700 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed = ?

m = mass of sand = 2 kg

c = heat capacity = $835J/kg^0C$

Initial temperature  = $T_i$ = $40^0C$

Final temperature= $T_f$  = $50^0C$

Change in temperature ,$\Delta T=T_f-T_i=(50-40)^0C=10^0C$

Putting in the values, we get:

$Q=2kg\times 835J/kg^0C\times 10^0C$

$Q=16700J$

16700 J of energy must be added to a 2-kilogram pile of it to increase its temperature from 40°C to 50°C