Answer:
V = 8.34m/s
Explanation:
Given that
1/2ke^2 = 1/2mv^2 ......1
Where e = 3.75cm = (3.75/100)m
e = 0.0375m
K = 500 N/m
m = 10g = 10/1000
= 0.01kg
Substitute the values into equation 1
0.5×500×(0.0375)^2 = 0.5×0.01×v^2
250×0.001395 = 0.005v^2
0.348 = 0.005v^2
v^2 = 0.348/0.005
v^2 = 69.6
V = √69.6
V = 8.34m/s
The ball launches at the speed of V = 8.34m/s
Answer: 3MeV electron
Explanation:
m_e={9.1\times 10^{-31} m_α=4\times m_e m_a={9.1\times 10^{-31}
m_p=1.67\times 10^{-27}
(a) K.E. Energy of electron =
=3MeV
=1.05\times10^{18}

(b) K.E. Energy of alpha particle =
=10MeV
=0.88\times10^{18}

(c) K.E. Energy of auger particle =
=0.1MeV
=0.035\times10^{18}

(d) K.E. Energy of proton particle =
=400keV
=0.766\times10^{14}
![v_p=\sqrt{0.766\times10^{14} } =0.875\times10^{7}[tex]\frac{m}{s}](https://tex.z-dn.net/?f=v_p%3D%5Csqrt%7B0.766%5Ctimes10%5E%7B14%7D%20%7D%20%3D0.875%5Ctimes10%5E%7B7%7D%5Btex%5D%5Cfrac%7Bm%7D%7Bs%7D)
from (a),(b),(c),and (d) we can clearly say that the velocity of the electron is more so the penetration of the electron will be deepest.
Answer:
Decreases.
Explanation:
When an object with potential energy falls to the ground, its potential energy decreases and kinetic energy increases.
Answer:
Explanation:
66 km/hr = 18.3 m/s
½mv² = ½kx²
k = mv²/x² = 1200(18.3²)/2.2² = 83,333 = 83 kN/m
Explanation:
We know that :
u = 29 mph = 12.96 m/s
S = 471 ft = 143.5 m
t = 8.5 sec

143.5 = 12.96 * 8.5 + 1/2 * a * 72.25
a = 66.68 / 72.25
a (Acceleration) = 0.92 m/sec^2
= 3.01 ft/sec^2