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loris [4]
3 years ago
8

40 POINTS

Physics
2 answers:
nexus9112 [7]3 years ago
6 0
I think is letter B) gravity
goldenfox [79]3 years ago
5 0

Answer:

<em>Well, I think the best answer will be is </em><em>B) Gravity. Good luck!</em>

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Calculate how fast the ball would be moving at the instant it leaves the projectile launcher of the spring is compressed by 3.75
Mnenie [13.5K]

Answer:

V = 8.34m/s

Explanation:

Given that

1/2ke^2 = 1/2mv^2 ......1

Where e = 3.75cm = (3.75/100)m

e = 0.0375m

K = 500 N/m

m = 10g = 10/1000

= 0.01kg

Substitute the values into equation 1

0.5×500×(0.0375)^2 = 0.5×0.01×v^2

250×0.001395 = 0.005v^2

0.348 = 0.005v^2

v^2 = 0.348/0.005

v^2 = 69.6

V = √69.6

V = 8.34m/s

The ball launches at the speed of V = 8.34m/s

6 0
3 years ago
Which of the following can penetrate the deepest (Please explain)
harkovskaia [24]

Answer: 3MeV electron

Explanation:

m_e={9.1\times 10^{-31}      m_α=4\times m_e    m_a={9.1\times 10^{-31}

m_p=1.67\times 10^{-27}

(a)  K.E. Energy of electron =\frac{1}{2}\times{m_e}\times{v_{e} ^{2}}=3MeV

v_{e} ^{2}=\frac{2\times3\times1.6\times10^{-19}\times10^{6}  }{9.1\times 10^{-31} }=1.05\times10^{18}

v_e=\sqrt{1.05\times10^{18} } = 1.025\times10^{9}\frac{m}{s}

(b) K.E. Energy of alpha particle =\frac{1}{2}\times{m_\alpha}\times{v_{\alpha} ^{2}}=10MeV

v_{\alpha} ^{2}= \frac{2\times10\times1.6\times10^{-19}\times10^{6}  }{4\times9.1\times 10^{-31} }=0.88\times10^{18}

v_\alpha=\sqrt{0.88\times10^{18} } =.94\times10^{9}\frac{m}{s}

(c) K.E. Energy of auger particle =\frac{1}{2}\times{m_a}\times{v_{a} ^{2}}=0.1MeV

v_{a} ^{2}=\frac{2\times0.1\times1.6\times10^{-19}\times10^{6}  }{9.1\times 10^{-31} }=0.035\times10^{18}

v_a=\sqrt{0.035\times10^{18} } =.19\times10^{9}\frac{m}{s}

(d)  K.E. Energy of proton particle =\frac{1}{2}\times{m_p}\times{v_{p} ^{2}}=400keV

v_{p} ^{2}=\frac{2\times400\times1.6\times10^{-19}\times10^{3}  }{1.67\times 10^{-27} }=0.766\times10^{14}

v_p=\sqrt{0.766\times10^{14} } =0.875\times10^{7}[tex]\frac{m}{s}

from (a),(b),(c),and (d) we can clearly say that the velocity of the electron is more so the penetration of the electron will be deepest.

6 0
3 years ago
As a falling apple, approaches the ground, its potential energy
attashe74 [19]

Answer:

Decreases.

Explanation:

When an object with potential energy falls to the ground, its potential energy decreases and kinetic energy increases.

7 0
2 years ago
Một xe nặng 1200kg trượt ngang với tốc độ 66km/h tới va vào một lò xò làm cho lò xò nắn lại một đoạn là 2,2m.Tính hằng số của lò
liberstina [14]

Answer:

Explanation:

66 km/hr = 18.3 m/s

½mv² = ½kx²

k = mv²/x² = 1200(18.3²)/2.2² = 83,333 = 83 kN/m

4 0
3 years ago
A car traveling 29 mi/h accelerates uniformly for 8.5 s, covering 471 ft in this time.What was its acceleration? Round your answ
Andrei [34K]

Explanation:

We know that :

u = 29 mph = 12.96 m/s

S = 471 ft = 143.5 m

t = 8.5 sec

s = ut +  \frac{1}{2} a {t}^{2}

143.5 = 12.96 * 8.5 + 1/2 * a * 72.25

a = 66.68 / 72.25

a (Acceleration) = 0.92 m/sec^2

= 3.01 ft/sec^2

8 0
3 years ago
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