At the end of the 2nd yr his balance is $440, = I = $14.08
At the end if the 3rd yr his balance is $600, = I = $21.12
$200 is deposited at the beginning of each year
End if the 1st yr SI = PRT/100 = 220 X 3.2 X 1/100 = $7.04
Start of the 2nd yr $220 + $220 = $440
End of the 2nd yr: SI = PRT/100 = 440 X 3.2 X 1/100 = $14.08
Start of the 3rd yr $440 + $220 = $660
End of the 3rd yr: SI = PRT/100 = 660X 3.2 X 1/100 = $21.12
At the end of th2 2nd yr his balance is 440, = I = $14.08
At the end if the 3rd yr his balance is $600, = I = $21.12
HE now has $660 in his account and has earned a total of 42.24 interest over the 3 years.
Answer:
No
Step-by-step explanation:
Because 6, 6 and 10 are not Pythagorean triplets.
Hence, it is not a right triangle.
X<264/203
A good site to use for problems like this is Wolfram Alpha, just google it and it should show up!
6 - 34 + 96 - 384 +...
a 1 = 6 , a 2 = a 1 * ( - 4 ) , a 3 = a 2 * ( - 4 ), a 4 = a 3 * ( - 4)...
a 5 = - 384 * ( - 4 ) = 1,536
a 6 = 1536 * ( - 4 ) = - 6,144
a 7 = - 6,144 * ( - 4 ) = 24,576
This is a sum of a geometric sequence:
S 7 = 6 - 24 + 96 - 384 + 1,536 - 6,144 + 24,576 = 19,662
Another way to solve this:
S 7 = a 1 * ( r^n - 1) / ( r - 1 ) = 6 * (( - 4) ^7 - 1 )/ (- 4 - 1)=
= 6 * (-16,385) / (-5 ) = 19,662
