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inn [45]
3 years ago
13

What mass of H2SO4 is contained in 60.00 mL of a 5.85 M solution of sulfuric acid

Chemistry
1 answer:
strojnjashka [21]3 years ago
5 0

First, we have to calculate the number of moles of H2SO4 in the solution:

V=60 mL = 0.06 L

c=5.85 mol/L

n=V×c=0.06×5.85=0.351 mol

Then we need to find the molar mass of H2SO4:

2×Ar(H) + Ar(S) + 4×Ar(O) =

=2 + 32 + 64 = 98 g/mol

Finally, we need to find the mass of H2SO4:

m=0.351 × 98 = 34.398 g

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