Answer:
See explanation below
Explanation:
First, you are not providing any data to solve this, so I'm gonna use some that I used a few days ago in the same question. Then, you can go and replace the data you have with the procedure here
The concentration of liquid sodium will be 8.5 MJ of energy, and I will assume that the temperature will not be increased more than 15 °C.
The expression to calculate the amount of energy is:
Q = m * cp * dT
Where: m: moles needed
cp: specific heat of the substance. The cp of liquid sodium reported is 30.8 J/ K mole
Replacing all the data in the above formula, and solving for m we have:
m = Q / cp * dT
dT is the increase of temperature. so 15 ° C is the same change for 15 K.
We also need to know that 1 MJ is 1x10^6 J,
so replacing all data:
m = 8.5 * 1x10^6 J / 30.8 J/K mole * 15 m = 18,398.27 moles
The molar mass of sodium is 22.95 g/mol so the mass is:
mass = 18,398.27 * 22.95 = 422,240.26 g or simply 422 kg rounded.
Answer:
temperature, refractive index, density, and hardness of an object
Explanation:
it is a bulk property, meaning that it is a physical property of a system that does not depend on the system size or the amount of material in the system
A. High energy radiation produced in the ozone layer. (:
Binders ; fillers. They are inert substances to hold pill shape and preserve the medication, its ph / etc.
Answer:
Explanation:
a. Oxidation : 2O + 4e^- ------> 2O^2-
b. Reduction: 2Sr - 4e- -------> Sr^2+
c. Balanced redox reaction
2Sr + O2 ------------> 2Sr O
Oxidation and reduction can be defined by various means, addition of oxygen, removal of hydrogen, removal of electrons. For this reaction, this definition is used, oxidation is the loss of electrons while reduction is the gaining of electrons.
In (a) oxidation half reaction, the valency of oxygen is zero and then moves into lossing two electrons resulting into -2 valency.
In (b) reduction half reaction, the valency of Sr is zero and gains electrons resulting into valency of 2.
In the overall redox reaction, Sr and O2 with valency of 0 each reacts together and form SrO with valency of 2 and -2 respectively, which gives 0 and then balances the equation.
