What happens is the PH changes
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The reaction between with calcium chloride can be shown as-
+
→
↓+2mCl. The molecular weight of
is 136.14g. The weight of sulfate ion is 96.06g. The molecular weight of
= (2×m + 96.06). From the reaction we can see that 1 mole of calcium chloride reacts with 1 moles
to produce 1 mole of calcium sulfate. Now 1.36g of calcium sulfate is equivalent to 1.36/136.14=9.989×
moles of calcium sulfate.
Thus, 9.989× moles of
reacts in this reaction.
Let assume the atomic mass of m is x thus the molecular weight of is 2x+96.
So we may write 9.989×× (2x+96) =1.42
Or, 2x + 96 = 142.146
Or, 2x = 46.146
Or, x = 23.073
Thus the atomic mass of m is 23.073. The atom (m) is sodium (Na).
Answer:
for given question is 2.79 and
is 0.52
{i- vant hoff’s constant ; Kb- constant ; m molarity }
M = no. of moles of the solute present in one kg of solution
Let the weight of amount of solute be “w” and its molecular mass be “M”
Let the mass of the solvent in the given question be “x”